A boy covers a distance of $25 km$ in $4$ hours partly on foot at the rate of $3.5 kmph$ and partly on cycle at $9 kmph$. Find the distance covered on foot.

Let the time spent walking be t hours, making the time on the cycle (4 minus t) hours. Using the formula Distance equals Speed multiplied by Time, the sum of the distances gives 3.5t plus 9(4 minus t) equals 25. Solving this equation, 3.5t plus 36 minus 9t equals 25, so 5.5t equals 11 and t equals 2 hours. The distance covered on foot is 3.5 multiplied by 2, which is 7 km.

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