A car covers a certain distance in $25$ hrs. if its reduces the speed by $\dfrac{1}{5}$th , the car covers $200 km$ less in that time . the speed of car is

Let the original speed of the car be S km/hr. Using the formula that distance equals speed multiplied by time, the original distance covered in 25 hours is 25 times S. If the speed is reduced by one-fifth, the new speed becomes four-fifths of S, and the distance covered in 25 hours is 25 multiplied by four-fifths of S. The difference between the original and new distances is 200 km, so 25 times S minus 25 times four-fifths of S equals 200. This simplifies to 5 times S equals 200, which means the original speed S is 40 km/hr.

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