Time, Speed and Distance Questions

Multiple choice
  1. 65.4 km/hr

  2. 72.8 km/hr

  3. 75.5 km/hr

  4. 78.9 km /hr

  5. 47 km/hr

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

First train: 156 km in 3 hours (3pm to 6pm) = 52 km/hr. Ratio of speeds = 5:7. If 5 units = 52, then 1 unit = 10.4. Second train = 7 units = 7 * 10.4 = 72.8 km/hr.

Multiple choice
  1. 7 minutes

  2. 8 minutes

  3. 8.57 minutes

  4. 9 minutes

  5. 9.20 minutes

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Relative speed = 3 + 4 = 7 km/h. Distance = 1 km. Time = Distance / Speed = 1/7 hours = 60/7 minutes = 8.5714 minutes.

Multiple choice
  1. 70 m

  2. 75 m

  3. 80 m

  4. 85 m

  5. 90 m

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The man and dog are moving in the same direction. The relative speed is 5 - 3 = 2 m/s. In 10 seconds, the dog covers 50 m and the man covers 30 m. The initial distance is 100 m. The new distance = 100 - (50 - 30) = 100 - 20 = 80 m.

Multiple choice
  1. 12:10 pm

  2. 12:40 pm

  3. 1:00 pm

  4. 1:20 pm

  5. 2:00 pm

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Jagdish distance at time t: 50(t-5). Chetan distance at time t: 70(t-7). We want 70(t-7) = 50(t-5) + 20. 70t - 490 = 50t - 250 + 20. 20t = 260. t = 13 (1:00 pm).

Multiple choice
  1. 2100 km

  2. 1950 km

  3. 1542 km

  4. 1430 km

  5. 1360 km

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Speed increases every 3 hours. 0-3h: 56km/h (dist=168). 3-6h: 58km/h (dist=174). 6-9h: 60km/h (dist=180). 9-12h: 62km/h (dist=186). 12-15h: 64km/h (dist=192). 15-18h: 66km/h (dist=198). 18-21h: 68km/h (dist=204). 21-24h: 70km/h (dist=210). 24-27h: 72km/h (dist=216). 27-30h: 74km/h (dist=222). Sum = 168+174+180+186+192+198+204+210+216+222 = 1950.

Multiple choice
  1. a

  2. b

  3. c

  4. d

  5. e

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Distance = 50 * 6 = 300 km. New speed = 60 km/hr. Time = 300 / 60 = 5 hours. Quantity I = 5 hours, Quantity II = 4 hours. Thus, Quantity I > Quantity II.

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I < Quantity II

  3. Quantity I ≥ Quantity II

  4. Quantity I ≤ Quantity II

  5. Quantity I = Quantity II or No relation

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let distance be D. Time at 40 km/hr = D/40. Time at 30 km/hr = D/30. Difference in time = 12 min late - (-10 min early) = 22 minutes = 22/60 hours. D/30 - D/40 = 22/60. (4D - 3D)/120 = 22/60. D = 120 * (22/60) = 44 km. Since 44 < 50, Quantity I < Quantity II.

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I < Quantity II

  3. Quantity I ≥ Quantity II

  4. Quantity I ≤ Quantity II

  5. Quantity I = Quantity II or No relation

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let speeds be u and v. (u-v) = 70/7 = 10. (u+v) = 70/2 = 35. Quantity I (sum of speeds) = 35. Quantity II = 25. Since 35 > 25, Quantity I > Quantity II.

Multiple choice
  1. 0 ms-1, 2 ms-1

  2. 2 ms-1, 0 ms-1

  3. 0 ms-1, 0 ms-1

  4. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Total distance = 120 m. Total time = 60 s. Average speed = 120 / 60 = 2 m/s. Displacement = 0 (since he returns to the start). Average velocity = 0 / 60 = 0 m/s.

Multiple choice
  1. 9 am

  2. 11 am

  3. 10 am

  4. 12 am

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

P travels for 1 hour alone (20 km). Remaining distance is 90 km. Relative speed is 20 + 25 = 45 km/hr. Time to meet = 90 / 45 = 2 hours after 8 am, which is 10 am.