Quantitative Aptitude

Time, Speed and Distance

2,165 Questions
All Core formulas and unit conversion 441 Boats and streams effective speed 396 Relative speed, meetings, and overtaking 375 Average speed 362 Early and late arrival 321 Proportional relationships 202 Stoppage time per hour 35 Train and stationary or moving object crossing 17 Races and dead heats 16

Time, Speed and Distance Questions

Multiple choice

Two trains starts from P and Q respectively and travel towards each other at a speed of 50 km/h and 40km/hr respectively. By the time they meet, the first train has travelled 100km more than the second. The distance between P and Q is:

  1. 500km

  2. 630km

  3. 660km

  4. 900km
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The trains travel for the same time before meeting, so their distances are in the ratio 50 : 40 = 5 : 4. The difference of one ratio part is 100 km, making the total distance 9 x 100 = 900 km.

Multiple choice

A and B travel the same distance at speeds of 9km/hr and 10km/hr respectively. If A takes 36 minutes more than B, the distance travelled by each is

  1. 48km

  2. 54km

  3. 60km

  4. 66km
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the distance be D km. The time taken by A is D/9 hours and by B is D/10 hours. Since A takes 36 minutes (which is 36/60 = 0.6 hours) more than B, we set up the equation D/9 - D/10 = 0.6, which simplifies to D/90 = 0.6, giving D = 54 km.

Multiple choice

A motor-cycle covers 40 km with a speed of 20 km/hr. find the speed of the motor-cycle for the next 40 km journey so that the average speed of the whole journey will be 30 km/hr.

  1. 70 km/hr

  2. 52.5 km/hr

  3. 60 km/hr

  4. 60.5 km/hr
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Average speed = Total distance / Total time. Total distance = 80 km. Average speed = 30 km/hr. Total time = 80 / 30 = 8/3 hours. Time for first 40 km = 40 / 20 = 2 hours. Time for next 40 km = 8/3 - 2 = 2/3 hours. Speed for next 40 km = 40 / (2/3) = 60 km/hr.

Multiple choice

Two places A and B are at a distance of 480Km. Sita started from A towards B at the speed of 40Kmph. After 2 hours Gita started from B towards A at speed of 60 Kmph. They meet at a Place C then what is the difference between the time taken by them to reach their destinations from Place C?

  1. 1 hour

  2. 2 hour

  3. 3 hour

  4. 4 hour

  5. Cannot be determined
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Sita travels 2 hours alone (80 km). Remaining distance = 400 km. Relative speed = 40 + 60 = 100 km/h. Time to meet = 400/100 = 4 hours. Sita travels 6 hours total (240 km from A). Gita travels 4 hours total (240 km from B). Time for Sita to reach B = 480/40 = 12 hours. Time for Gita to reach A = 480/60 = 8 hours. Time remaining for Sita from C = 12 - 6 = 6 hours. Time remaining for Gita from C = 8 - 4 = 4 hours. Difference = 2 hours.

Multiple choice

Sanjay and Suresh started driving from two opposite points 300 km apart. The speed of Suresh's car is 60 kmph while Sanjay is two-third, as fast as Suresh. If they start at the same time, after how much time will they meet each other for the first time?

  1. 15 hr

  2. 7.5 hr

  3. 5 hr

  4. 3 hr
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Suresh speed = 60 kmph. Sanjay speed = (2/3) * 60 = 40 kmph. Relative speed = 60 + 40 = 100 kmph. Time = Distance / Relative Speed = 300 / 100 = 3 hours.

Multiple choice

The ratio between the speed of a train and a car is 20 : 19 respectively. Also, a bus covered a distance of 640 km in 8 h. The speed of the bus is 4/5 th of the speed of the train. How much distance will the car cover in 7 h?

  1. 655 km

  2. 645 km

  3. 665 km

  4. 685 km
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Bus speed = 640 / 8 = 80 km/h. Train speed = 80 / (4/5) = 100 km/h. Ratio of train to car = 20:19, so car speed = (19/20) * 100 = 95 km/h. Distance for car in 7h = 95 * 7 = 665 km.