Quantitative Aptitude

Time, Speed and Distance

2,165 Questions
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Time, Speed and Distance Questions

Multiple choice

The distance covered in fixed time interval are mentioned for four different bodies. Which of these bodies is travelling with a uniform speed?

  1. Time (s) Distance (m) 0-3 6 3-6 5 6-9 6 9-12 5 12-15 6

  2. Time (s) Distance (m) 0-3 5 3-6 5 6-11 5 11-16 5 16-20 5

  3. Time (s) Distance (m) 0-5 10 5-10 10 10-15 8 15-20 10 20-25 12

  4. Time (s) Distance (m) 0-10 20 10-20 20 20-30 20 30-40 20 40-50 20
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Uniform speed means the object covers equal distances in equal time intervals. Option D shows a constant distance of 20m for every 10s interval, indicating a constant speed of 2m/s.

Multiple choice

A police saw a Thief at a distance of 2km. When Police started chasing him Thief also started running. If the ratio of Speeds of Police to Thief is 5:4. Then thief was caught at a certain distance then how many Kms did police run to catch the Thief?

  1. 5 Km

  2. 6 Km

  3. 8 Km

  4. 10 Km

  5. Cannot be determined
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Since the ratio of speeds is 5:4, the distances covered in the same time are also in a 5:4 ratio. Let distance of police be 5x and thief be 4x. The initial gap is 2km, so 5x - 4x = 2km, meaning x = 2. Police distance = 5 * 2 = 10 km.

Multiple choice

Ravi travels first 1/4th of the total distance at the speed of 10 kmph and the next 1/4th distance at the speed of 5 kmph and the last half of the distance at the speed of 10 kmph. What will be the average speed?

  1. 5.0 km/hr

  2. 8.0 km/hr

  3. 8.33 km/hr

  4. 9.0 km/hr

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Average speed is total distance divided by total time. Let total distance be D. Time = (D/4)/10 + (D/4)/5 + (D/2)/10 = D/40 + D/20 + D/20 = D/40 + 2D/40 + 2D/40 = 5D/40 = D/8. Average speed = D / (D/8) = 8 km/hr.

Multiple choice

A policeman and thief noticed each other at a distance of 150 m between them. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 8 kmph and 11 kmph, respectively. What is the distance between them after 2 minutes?

  1. 50 m

  2. 60 m

  3. 75 m

  4. 90 m

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The relative speed of the policeman with respect to the thief is 11 - 8 = 3 km/h. In 2 minutes (1/30 hours), the policeman gains 3 * (1/30) = 0.1 km = 100 m on the thief. The initial distance was 150 m, so the remaining distance is 150 - 100 = 50 m.

Multiple choice

A and B are at a distance of 150 km from each other. A started travelling towards B on his bicycle at a speed of 30 kmph. One hour later, B also started travelling towards A on his bicycle at a speed of 20 kmph. How much distance does B cover before they meet?

  1. 33 km

  2. 36 km

  3. 48 km

  4. 56 km

  5. 72 km
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

In the first hour, A travels 30 km, reducing the distance between them to 120 km. Once B starts, they travel toward each other with a combined relative speed of 50 kmph (30 + 20). It takes them 120 / 50 = 2.4 hours to meet, during which B covers a distance of 20 kmph * 2.4 hours = 48 km.

Multiple choice

For a practice session, army personnel in a two-kilometre long group are walking one behind the other at a uniform speed. A commanding officer starts from the back, walks forward till he reaches the front. Then he returns with the same speed till he reaches the last army-man. When he gets to the last army-man, the last army-man has reached exactly the spot where the army-man at the front was when the officer started. What is the total distance travelled by the officer in this whole operation?

  1. 4.24 km

  2. 4.42 km

  3. 4.62 km

  4. 4.83 km

  5. 4.92 km
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let officer speed be v and group speed be u. Time to reach front: t1 = 2 / (v - u). Time to return to back: t2 = 2 / (v + u). Total time T = t1 + t2. In time T, the group moves distance uT = 2. So u = 2/T. Total distance = vT. Solving leads to v/u = sqrt(2) + 1. Total distance = 2 * (v/u) = 2 * (1 + sqrt(2)) = 4.828 km.

Multiple choice

A truck goes from place A to place B covering a distance 150 km with a uniform speed. Another car, starting from A, at a speed 25 km/hr higher than that of the truck, reaches B, 3 hrs earlier. Find the speed of the truck.

  1. 20 km/hr

  2. 30 km/hr

  3. 25 km/hr

  4. 50 km/hr

  5. None of these
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let speed of truck be v. Speed of car = v+25. Time truck = 150/v. Time car = 150/(v+25). 150/v - 150/(v+25) = 3. 50/v - 50/(v+25) = 1. 50(v+25-v) = v(v+25). 1250 = v^2 + 25v. v^2 + 25v - 1250 = 0. (v+50)(v-25) = 0. v = 25.

Multiple choice

A person goes to college at a speed of 4 km/hr and gets late by 15 minutes. If he had travelled at 5 km/hr, he would have got late by 9 minutes. What should be his speed such that he reaches his college 10 minutes early?

  1. 45 km/hr

  2. 24 km/hr

  3. 52 km/ hr

  4. 18 km/hr

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let distance be d. Time taken at 4 km/hr = d/4. Time taken at 5 km/hr = d/5. Difference = (d/4 - d/5) = 15 - 9 = 6 mins = 0.1 hr. d/20 = 0.1, d = 2 km. Time to reach on time = d/4 - 15/60 = 0.5 - 0.25 = 0.25 hr. To reach 10 mins early, time = 0.25 - 10/60 = 0.25 - 0.166 = 0.0833 hr. Speed = 2 / 0.0833 = 24 km/hr.

Multiple choice

A boy travels from Kohara to Jalandhar at a speed of 80 km/hr. On the return journey, he decreases his speed by 25%. If the distance between Kohara and Jalandhar is 60 km, find the extra time taken by the boy during his return journey.

  1. 10 min

  2. 12 min

  3. 18 min

  4. 15 min

  5. None of these
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Outward speed = 80 km/hr. Outward time = 60/80 = 0.75 hours (45 min). Return speed = 80 - 25% of 80 = 60 km/hr. Return time = 60/60 = 1 hour (60 min). Extra time = 60 - 45 = 15 min.