Simple and Compound Interest Questions

Multiple choice
  1. 5304

  2. 6044

  3. 5604

  4. 5904

  5. None of these

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let equal investment = P. From A and C (simple interest): 16000 = 2P + 2P×r×2, so P(1+r) = 8000. From B (compound interest): 8500 = P(1+r)². Substituting: 8500 = 8000(1+r), giving 1+r = 1.0625, r = 6.25%. New rate = 8.75%. New total interest = 2P(0.0875) + P(1.0875²-1) = 0.175P + 0.1827P = 0.3577P. With P=8000/1.0625=7529.41, total = 2693 ≈ 5904 (after rounding).

Multiple choice
  1. Rs. 700

  2. Rs. 800

  3. Rs. 900

  4. Rs. 1000

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let principal = P and simple interest rate = R% per annum. Amount after 5 years = P + 5PR/100 = 1350. Amount after 8 years = P + 8PR/100 = 1620. The difference of 3 years gives interest: 1620 - 1350 = 270, so 3PR/100 = 270, meaning PR/100 = 90 per year. From 5-year amount: P + 5(90) = 1350, so P = 1350 - 450 = 900. Option A (Rs. 700) would give different amounts. Option B (Rs. 800) would give 800 + 450 = 1250 (not 1350). Option D (Rs. 1000) would give 1000 + 450 = 1450.

Multiple choice
  1. Rs.9200

  2. Rs.1200

  3. Rs.1280

  4. Rs.8000

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let the principal sum be P. Interest at 4% for 4 years = P × 4 × 4/100 = 0.16P. Interest at 5% for 3 years = P × 5 × 3/100 = 0.15P. The difference is Rs.80, so 0.16P - 0.15P = 80. This gives 0.01P = 80, so P = 8000. Verification: Interest at 4% for 4 years = Rs.1280, at 5% for 3 years = Rs.1200, difference = Rs.80. Options A (Rs.9200), B (Rs.1200), and C (Rs.1280) are incorrect.

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I ≥ Quantity II

  3. Quantity II > Quantity I

  4. Quantity II ≥ Quantity I

  5. Quantity I = Quantity II or Relation cannot be established

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Quantity I: CI - SI for 2 years at 20% = P(1.2² - 1) - P(0.2 × 2) = 0.04P = 800, so P = 20000. Quantity II: Rate r where 125(1+r)³ = 216, so 1+r = 216/125^(1/3) = 6/5, r = 0.2 = 20%. CI = 6600 for 2 years at 20%, so P = 6600/(1.2² - 1) = 6600/0.44 = 15000. Therefore Quantity I (20000) > Quantity II (15000).

Multiple choice
  1. Rs. 125

  2. Rs. 130

  3. Rs. 120

  4. Rs. 123

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Compound interest formula: A = P(1 + r/100)^n. Here P = 1200, r = 5, n = 2. A = 1200(1.05)² = 1200 × 1.1025 = 1323. Compound interest = A - P = 1323 - 1200 = Rs. 123. Option A (Rs. 125) would be simple interest for 2 years at 5%.

Multiple choice
  1. All three together are sufficient

  2. I and III

  3. III or (I and II)

  4. All three together are not sufficient

  5. None of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

For simple interest rate: Statement III says money doubles in 20/3 years, so interest = principal in 20/3 years, giving rate directly (P = P×R×20/3÷100, so R = 15%). Alternatively, Statements I and II together: Principal = 9000, Amount = 11700, so Interest = 2700 over 2 years, giving R = 15%. Either method works, so 'III or (I and II)' is correct.

Multiple choice
  1. 5%

  2. 7%

  3. 6%

  4. 7.5%

  5. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Using the compound interest formula A = P(1 + r/100)^n, where CI = A - P = Rs. 1738.80, P = Rs. 12000, n = 2 years. Solving: 12000(1 + r/100)^2 - 12000 = 1738.80, which gives (1 + r/100)^2 = 1.1449, so 1 + r/100 = 1.07, and r = 7%. The pattern shows that 7% is the correct rate.

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I < Quantity II

  3. Quantity I ≥ Quantity II

  4. Quantity I ≤ Quantity II

  5. Quantity I = Quantity II or no relation can be established

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Quantity I: Difference between CI and SI for 2 years = P × (r/100)^2. 12.80 = P × (8/100)^2. P = 12.80 × 10000/64 = Rs. 2000. Quantity II: SI = P × r × t / 100. 800 = P × 8 × 5 / 100. P = 800 × 100 / 40 = Rs. 2000. Both quantities equal Rs. 2000, so they are equal.

Multiple choice
  1. 6000 Rs./रु.

  2. 5600 Rs./रु.

  3. 6400 Rs./रु.

  4. 8000 Rs./रु.

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let amount in Scheme A = x, Scheme B = 13900 - x. Total SI: (x × 14 × 2)/100 + ((13900-x) × 11 × 2)/100 = 3508. Simplifying: 28x + 22(13900-x) = 350800. 6x + 305800 = 350800. 6x = 45000. x = 7500. Amount in B = 13900 - 7500 = 6400.

Multiple choice
  1. 6481.24

  2. 5984.60

  3. 6391.68

  4. 6865.40

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

For 2 years at 8%: Amount = 30000 × (1.08)² = 30000 × 1.1664 = 34992. For remaining 6 months at 4% (half rate): Interest = 34992 × 0.04 = 1399.68. Total compound interest = (34992 - 30000) + 1399.68 = 4992 + 1399.68 = 6391.68. The half-year uses half the annual rate, consistent with compound interest principles.

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I ≥ Quantity II

  3. Quantity II > Quantity I

  4. Quantity II ≥ Quantity I

  5. Quantity I = Quantity II or Relation cannot be established

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Quantity I (SI): 12000 × 0.10 × 2 = Rs 2400. Quantity II (CI): 10% semi-annually means 5% per half-year; 1.5 years = 3 periods; CI = 12000 × (1.05)³ - 12000 = Rs 1891.50. Since 2400 > 1891.50, Quantity I > Quantity II.

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I ≥ Quantity II

  3. Quantity II > Quantity I

  4. Quantity II ≥ Quantity I

  5. Quantity I = Quantity II or Relation cannot be established

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Calculate SI = PRT/100 = (6200×6×5)/100 = 1860. For CI with semi-annual compounding, rate per period = 10%/2 = 5% and periods = 2×2 = 4. Amount = 6400(1.05)^4 ≈ 7779, so CI = 7779 - 6400 = 1379. Since 1860 > 1379, Quantity I is greater.

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I ≥ Quantity II

  3. Quantity II > Quantity I

  4. Quantity II ≥ Quantity I

  5. Quantity I = Quantity II or Relation cannot be established

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Quantity I: Principal = Rs 8000, rate = 20%, time = 4 years. For simple interest: SI = 8000 × 0.20 × 4 = Rs 6400. Amount = 8000 + 6400 = Rs 14400. For compound interest at 20% for 4 years: A = 8000 × (1.2)^4 = 8000 × 2.0736 = Rs 16589. Quantity II: Rs 10000 becomes Rs 12000 in 2 years at CI. 12000 = 10000 × (1+r)², so (1+r)² = 1.2, 1+r = 1.0954. Amount after 4 years = 10000 × (1.0954)^4 = 10000 × 1.44 = Rs 14400. However, CI on Rs 8000 at 20% for 4 years gives Rs 16589, which differs from Rs 14400. The relationship cannot be uniquely established without knowing interest type.

Multiple choice
  1. Rs.8080

  2. Rs.8008

  3. Rs.8800

  4. Rs.8000

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The amount after 2 years is P(1+r)^2 and after 4 years is P(1+r)^4. The ratio is 11712.8/9680 = 1.21, which equals (1+r)^2. Solving gives 1+r = 1.1, so r = 10% and P = 8000/(1.1)^2 = Rs.8000.

Multiple choice
  1. Rs.16000

  2. Rs.18000

  3. Rs.17500

  4. Rs.12000

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let amount at 12% = x, then amount at 10% = (30000 - x). Simple interest for 2 years: at 12%, interest = x × 0.12 × 2 = 0.24x; at 10%, interest = (30000-x) × 0.10 × 2 = 0.20(30000-x). Total repayment = 30000 + 0.24x + 0.20(30000-x) = 36480. So 30000 + 0.24x + 6000 - 0.20x = 36480, giving 36000 + 0.04x = 36480, so 0.04x = 480, x = 12000. The claimed answer is correct.