Quantitative Aptitude
Simple and Compound Interest
3,394 Questions
Simple and Compound Interest Questions
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Rs./रु.4320
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Rs./रु.6240
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Rs./रु.7944
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Rs./रु.12480
C
Correct answer
Explanation
60% increase in 6 years at SI means rate = 60/6 = 10% per annum. For CI on Rs.24000 for 3 years at 10%: Amount = 24000 × (1.1)^3 = 24000 × 1.331 = Rs.31944. CI = 31944 - 24000 = Rs.7944. The key is converting the SI information to find the rate first.
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Rs.16280
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Rs.16440
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Rs.12640
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Rs.16420
A
Correct answer
Explanation
Given borrowed sum = 28000, which is 175% of x, so x = 28000/1.75 = 16000. After year 1: Amount = 28000(1.1) = 30800. Repayment of 16000 leaves 14800. After year 2: 14800(1.1) = 16280. This is the final payment needed. The compound interest formula A = P(1+r)^n is applied sequentially with the repayment.
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Rs.16290
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Rs.15500
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Rs.16350
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Rs.16500
C
Correct answer
Explanation
Under simple interest, if amount becomes twice the principal in T years, then interest = principal, so rate r = 100/T %. For 2T years at same rate, interest = P × r × 2T/100 = P × (100/T) × 2T/100 = 2P. Amount = P + 2P = 3P. For principal Rs. 5450, amount = 3 × 5450 = Rs. 16350.
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Rs. 1908
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Rs. 1608
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Rs. 1806
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Rs. 1904
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None of these
A
Correct answer
Explanation
Using the compound interest formula A = P(1+r)ⁿ: A = 7500(1.12)² = 7500 × 1.2544 = 9408. Compound Interest = A - P = 9408 - 7500 = 1908. Option A is correct.
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Rs.2220
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Rs.2230
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Rs.2320
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Rs.2200
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Rs.2222
B
Correct answer
Explanation
For simple interest: Amount after 5 years = P + SI = P + P×R×5/100 = P(1 + 5R/100) = 10962. After 8 years: P(1 + 8R/100) = 13003.2. Difference: P(3R/100) = 13003.2 - 10962 = 2041.2. So PR = 2041.2 × 100/3 = 68040. From 5 year equation: P + 5 × 68040/100 = P + 3402 = 10962, so P = 7560, R = 9%. CI for same principal at 9% for appropriate time = 7560(1.09)^n - 7560. Assuming 8 years: CI = 7560 × 1.99256 - 7560 ≈ 15064 - 7560 = 7504. But answers are around 2200. Let me reconsider - maybe 3 years CI? For 3 years: 7560(1.09)³ - 7560 = 9799 - 7560 = 2239. So approximately 2230, which matches option B.
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Rs.310.80
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Rs.421.70
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Rs.315.90
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Rs.350.70
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None of these
C
Correct answer
Explanation
Simple Interest: 303.60 = P×3×4/100, so P = 30360/12 = Rs. 2530. Compound Interest for 3 years at 4%: Amount = 2530(1.04)^3 = 2530×1.124864 = Rs. 2845.90. CI = 2845.90 - 2530 = Rs. 315.90. Answer C is correct.
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Rs.20000
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Rs.25000
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Rs.30000
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Rs.40000
B
Correct answer
Explanation
Let principal be P. After 2 years at 20% SI: P(1 + 0.20×2) = 1.4P. Next 2 years at 12% CI: 1.4P(1.12)² = 1.4P × 1.2544 = 1.75616P. Given 1.75616P = 43904, so P = 43904/1.75616 ≈ 25000. The calculation uses SI formula A = P(1 + rt) and CI formula A = P(1 + r)ⁿ.
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Rs.10000
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Rs.6000
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Rs.12000
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Rs.8000
D
Correct answer
Explanation
For half-yearly compounding, rate = 10% per period for 3 periods. CI factor = 1.1³ = 1.331. SI for 1.5 years at 20% = 1 + 0.2×1.5 = 1.3. Difference: 1.331P - 1.3P = 0.031P = 248. So P = 248/0.031 = 8000. Key insight: CI compounded half-yearly means rate/2 for 2×time periods.
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Rs.334.95
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Rs.339.95
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Rs.354.95
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Rs.358.95
A
Correct answer
Explanation
Compound Interest = P[(1 + r/100)^n - 1]. For P=5500, r=3%, n=2: CI = 5500[(1.03)² - 1] = 5500[1.0609 - 1] = 5500 × 0.0609 = Rs.334.95.
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20000
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20050
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22000
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22050
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25000
A
Correct answer
Explanation
After giving 50% to wife, remaining amount = Rs. 42050. Son A (15 years) gets amount P_A, son B (13 years) gets amount P_B. A invests for 3 years (until 18), B invests for 5 years (until 18). At 5% CI: P_A(1.05)^3 = P_B(1.05)^5. Solving: P_A/P_B = (1.05)^5/(1.05)^3 = (1.05)^2 = 1.1025. Also P_A + P_B = 42050. Substituting: 1.1025P_B + P_B = 42050, so 2.1025P_B = 42050, giving P_B ≈ Rs. 20000.
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18 years
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21 years
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24 years
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15 years
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None of these
D
Correct answer
Explanation
If an amount doubles in 5 years with compound interest, the relationship is 2 = (1+r)⁵, so (1+r)⁵ = 2. For eight times, we need (1+r)ⁿ = 8 = 2³ = [(1+r)⁵]³ = (1+r)¹⁵. Therefore n = 15 years. Option D is correct.
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Rs.12,000
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Rs.15,450
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Rs.16,620
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Rs.14,440
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None of these
E
Correct answer
Explanation
Let first deposit be x and second be y. Total: x + y = 25300. After 4 years at 20% CI: x(1.2)⁴ = x × 2.0736. After 3 years at 20% CI: y(1.2)³ = y × 1.728. These amounts are equal: 2.0736x = 1.728y → y = 1.2x. Substituting: x + 1.2x = 25300 → 2.2x = 25300 → x = 11500. So y = 25300 - 11500 = 13800. Checking: 11500 × 2.0736 = 23846.4 and 13800 × 1.728 = 23846.4. The 3-year deposit is Rs. 13800, which matches none of A-D. Option E (None of these) is correct.
A
Correct answer
Explanation
Difference in simple interest = P*R1*T/100 - P*R2*T/100 = P*T*(R1-R2)/100. Given: 2000*3*(r1-r2)/100 = 120. So 60*(r1-r2) = 120, hence r1-r2 = 2%. The principal and time cancel out in the difference.
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Rs./रुपये 725
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Rs./रुपये 816
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Rs./रुपये 600
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Rs./रुपये 520
B
Correct answer
Explanation
From SI = P×R×T/100, we get 2000 = P×4×5/100, so P = 10000. For CI in 2 years at 4%, use formula CI = P[(1 + R/100)^2 - 1] = 10000[(1.04)^2 - 1] = 10000[1.0816 - 1] = 816. The key is finding principal from SI first, then applying CI formula.
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1040
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1020
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1060
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1200
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None of these
A
Correct answer
Explanation
From SI formula, P = (6500 × 100)/(13 × 8) = 6250. CI for 2 years at 8% = 6250 × [(1.08)² - 1] = 6250 × 0.1664 = 1040. The key is finding principal from the simple interest information first.