Simple and Compound Interest Questions

Multiple choice
  1. $ $ 20,000$
  2. $ $ 15,000$
  3. $ $ 12,000$
  4. $ $ 10,000$
  5. $ $ 9,000$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The rule of 70 states that money doubles in 70/8 = 8.75 years. In 18 years, the money doubles approximately twice (18 / 8.75 is slightly more than 2). Doubling \$5000 twice results in \$5000 * 2 * 2 = $20,000.

Multiple choice
  1. Rs. 116.64

  2. Rs. 116.00

  3. Rs. 120

  4. Rs. 108

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Principal P. Interest for 1st year = P * 0.08 = 100, so P = 1250. Amount after 1st year = 1350. Interest for 2nd year = 1350 * 0.08 = 108. Amount after 2nd year = 1350 + 108 = 1458. Interest for 3rd year = 1458 * 0.08 = 116.64.

Multiple choice
  1. $\displaystyle \frac { w }{ 1+1.08 } $
  2. $\displaystyle \frac { w }{ 1.08+1.16 } $
  3. $\displaystyle \frac { w }{ 1.16+1.24 } $
  4. $\displaystyle \frac { w }{ 1.08+{ \left( 1.08 \right) }^{ 2 } } $
  5. $\displaystyle \frac { w }{ { \left( 1.08 \right) }^{ 2 }+{ \left( 1.08 \right) }^{ 3 } } $
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

After 1 year, the account has x * 1.08. Then another x is added, so the balance is x * 1.08 + x. After the second year, this amount earns 8% interest: (x * 1.08 + x) * 1.08 = w. So, w = x * (1.08^2 + 1.08). Therefore, x = w / (1.08^2 + 1.08).

Multiple choice
  1. $\displaystyle 1,000 \left(1 + \frac{5-3}{1,200}\right)^{12}$
  2. $\displaystyle 1,000 \left(1 + \frac{\displaystyle \frac{5}{3}}{1,200}\right)^{12}$
  3. $\displaystyle \frac{1,000 \left(1 + \displaystyle \frac{5}{1,200}\right)^{12}}{1,000 \left(1 + \displaystyle \frac{3}{1,200}\right)^{12}}$
  4. $\displaystyle 1,000 \left(1 + \displaystyle \frac{5}{1,200}\right)^{12} - \displaystyle 1,000 \left(1 + \displaystyle \frac{3}{1,200}\right)^{12}$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The amount generated is A(r) = 1000 * (1 + r/1200)^12. Additional money at 5% vs 3% is A(5) - A(3).

Multiple choice
  1. Rs. $13000 $   in scheme $A$, Rs. $12000$  in scheme $B$
  2. Rs. $12000$  in scheme $A$, Rs. $10000$ in scheme $B$
  3. Rs. $ 11000$  in scheme $A$, Rs. $10000$  in scheme $B$
  4. Rs. $10000$  in scheme $A$, Rs.  $13000$  in scheme $B$
Reveal answer Fill a bubble to check yourself
B Correct answer
Multiple choice
  1. Both (i) and (iii)

  2. Both (ii) and (iii)

  3. Both (i) and (ii)

  4. Any two of the three

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Simple Interest (SI) = P * R * T / 100. (i) 690 = P + P * R * 3 / 100. (ii) 750 = P + P * R * 5 / 100. (iii) R = 5. With any two statements, we have two variables (P and R) or can solve for P using the difference in interest over time.

Multiple choice
  1. 6 years

  2. 5 years

  3. 4 years

  4. 3 years

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Using the compound interest formula, we have 608 = 500 * (1.04)^n, which simplifies to 1.04^n = 1.216. Calculating the powers of 1.04, we find that 1.04^5 is approximately 1.2167, making 5 years the closest integer duration for the investment to reach 608.