Multiple choice

Susan invested certain amount of money in two schemes $A$ and $B$, which offer interest at the rate of $8\%$ per annum and $9\%$ per annum, respectively. She received Rs. $1860$ as annual interest. However, had she interchanged the amount of investments in the two schemes, she would have received Rs. $20$ more as annual interest. How much money did she invest in each scheme?

  1. Rs. $13000 $   in scheme $A$, Rs. $12000$  in scheme $B$
  2. Rs. $12000$  in scheme $A$, Rs. $10000$ in scheme $B$
  3. Rs. $ 11000$  in scheme $A$, Rs. $10000$  in scheme $B$
  4. Rs. $10000$  in scheme $A$, Rs.  $13000$  in scheme $B$
Reveal answer Fill a bubble to check yourself
B Correct answer
AI explanation

Using the simple interest formula, the two equations from the given conditions are 0.08A + 0.09B = 1860 and 0.09A + 0.08B = 1880. Multiplying by 100 gives 8A + 9B = 186000 and 9A + 8B = 188000. Subtracting the first equation from the second gives A - B = 2000, and adding them gives 17A + 17B = 374000, or A + B = 22000. Solving this system yields A = 12000 and B = 10000. Therefore, Rs. 12000 was invested in scheme A and Rs. 10000 in scheme B.

Keep practicing — related questions