Quantitative Aptitude
Simple and Compound Interest
3,394 Questions
Simple and Compound Interest Questions
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£229.67
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£231.53
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£234.92
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£238.32
B
Correct answer
Explanation
Amount = P(1 + r/100)^n = 200(1 + 5/100)^3 = 200(1.05)^3 = 200 * 1.157625 = 231.525. Rounded to two decimal places, this is 231.53.
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1 year
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2 years
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3 years
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4 years
B
Correct answer
Explanation
For 2 years, the amount is 30000 x 1.07^2 = 34347. Since the stated compound interest equals the final amount in the question's wording, the intended duration is 2 years.
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£45932.58
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£44814.5
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£43945.28
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£43546.25
A
Correct answer
Explanation
Principal P = 39553. Rate r = 2.5% per annum = 0.625% per quarter. Time n = 6 years = 24 quarters. Amount = P(1 + r/100)^n = 39553 * (1 + 0.00625)^24 = 39553 * (1.00625)^24. (1.00625)^24 is approx 1.16129. 39553 * 1.16129 = 45932.58.
B
Correct answer
Explanation
Let the principal be P and rate be r. Interest for year 1 = Pr = 2000. Interest for year 2 = (P + Pr)r = 2500. So, Pr + Pr^2 = 2500. Substituting Pr = 2000, we get 2000 + 2000r = 2500, so 2000r = 500, r = 0.25 or 25%.
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Rs. 2215
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Rs. 2500
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Rs. 2515
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Rs. 2415
D
Correct answer
Explanation
The interest for the first year is 15% of Rs. 14000, which is Rs. 2100, making the principal for the second year Rs. 16100. The interest for the second year is then 15% of Rs. 16100, which equals Rs. 2415.
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Rs. 2,145
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Rs. 2,000
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Rs. 2,045
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Rs. 2,100
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None of these
A
Correct answer
Explanation
Year 1: Interest = 3000 * 0.1 = 300. Payment 800 covers 300 interest, 500 principal. Balance = 2500. Year 2: Interest = 2500 * 0.1 = 250. Payment 800 covers 250 interest, 550 principal. Balance = 1950. Year 3: Interest = 1950 * 0.1 = 195. Total to pay = 1950 + 195 = 2145.
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Rs. 1800.00
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Rs. 2299.61
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Rs. 2200.00
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Rs. 2199.60
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None of these
B
Correct answer
Explanation
Year 1: Interest = 3000 * 0.06 = 180. Payment = 400. Principal reduction = 400 - 180 = 220. New principal = 2780. Year 2: Interest = 2780 * 0.06 = 166.8. Principal reduction = 400 - 166.8 = 233.2. New principal = 2546.8. Year 3: Interest = 2546.8 * 0.06 = 152.808. Principal reduction = 400 - 152.808 = 247.192. Final amount = 2546.8 - 247.192 = 2299.608.
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11 years
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10 years
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16 years
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13 years
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None of these
B
Correct answer
Explanation
Simple interest: Amount in 8 years - Amount in 3 years = 5 years interest = 7400 - 5900 = 1500. Interest per year = 300. Principal = 5900 - 3*300 = 5000. We want amount = 8000, so interest needed = 3000. Time = 3000 / 300 = 10 years.
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Rs. 50,000
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Rs. 40,500
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Rs. 55,000
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Rs. 60,000
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None of these
A
Correct answer
Explanation
Let P be the sum. Simple interest at 6% is 0.06P. Compound interest half-yearly at 6% per annum (3% per half-year) for one year is P(1 + 0.03)^2 - P = P(1.0609) - P = 0.0609P. The gain is 0.0609P - 0.06P = 0.0009P. Setting 0.0009P = 45 gives P = 45 / 0.0009 = 50,000.
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Rs. 600
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Rs. 960
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Rs. 2400
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Rs. 800
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None of these
C
Correct answer
Explanation
For 3 years at 5%, the compound interest factor is (1.05)^3 - 1 = 0.157625. Sum = 2522 / 0.157625 = 16000. Simple interest for 6 years at 2.5% is 16000 * 0.025 * 6 = 2400.
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8.24%
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8.3%
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8.2%
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8.01%
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None of these
A
Correct answer
Explanation
Nominal rate 8% quarterly means 2% per quarter. Effective rate = (1 + 0.02)^4 - 1 = 1.082432 - 1 = 0.082432 or 8.24%.
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Rs. 1,500
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Rs. 1,480
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Rs. 1,200
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Rs. 620
A
Correct answer
Explanation
Difference between CI and SI for 2 years = P * (r/100)^2. 7.35 = P * (7/100)^2 = P * 0.0049. P = 7.35 / 0.0049 = 1500.
C
Correct answer
Explanation
For compound interest, 15000(1 + r)^2 = 18816. The multiplier is 18816/15000 = 1.2544 = 1.12^2, so r = 0.12, or 12% per annum.
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2 years
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3 years
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4 years
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5 years
B
Correct answer
Explanation
Using the compound interest formula A = P(1 + r/100)^n, we have 5955 = 5000(1.06)^n. Dividing gives 1.191 = (1.06)^n. Since 1.06^3 is approximately 1.191, n = 3 years.
B
Correct answer
Explanation
Using the compound interest formula A = P(1 + r)^t, we want 2P = P(1.05)^t, so 2 = (1.05)^t. Using logarithms or estimation, 1.05^14 is approximately 1.98 and 1.05^15 is approximately 2.078. Therefore, it takes 15 years to exceed the doubling point.