Quantitative Aptitude

Profit, Loss and Discount

2,604 Questions
All Basic CP/SP Percentage Relationship 874 Marked Price, Markup, and Discount 786 Partial Sales and Multiple Transactions 338 Successive Discounts 218 Cost Price of X = Selling Price of Y 180 Faulty Weight or Measure 126 Equal Profit and Loss Rates 57 Free-item Offers 23 Price and Consumption Variation 1

Profit, Loss and Discount Questions

Multiple choice introduction to ratio and percentages comparing quantities maths

On selling $17$ balls at $Rs. 720$, there is a loss equal to the cost price of $5$ balls. The cost price of a ball is:

  1. $Rs. 45$
  2. $Rs. 50$
  3. $Rs. 55$
  4. $Rs. 60$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

$(C.P.\ of\ 17\ balls) - (S.P.\ of\ 17\ balls) = (C.P.\ of\ 5\ balls)$
$\Rightarrow$ C.P. of $12\ balls = S.P.\ of\ 17\ balls = Rs. 720$.
$\Rightarrow C.P.\ of\ 1\ ball = Rs. \left (\dfrac {720}{12}\right )= Rs. 60$.

Multiple choice introduction to ratio and percentages comparing quantities maths

If selling price is doubled, the profit triples. Find the profit percent.

  1. $66\dfrac {2}{3}$
  2. $100$
  3. $105\dfrac {1}{3}$
  4. $120$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let C.P. be $Rs. x$ and S.P. be $Rs. y$.
Then, $3(y - x) = (2y - x) \Rightarrow y = 2x$.
$Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x$.
$\therefore Profit$ % $= \left (\dfrac {x}{x}\times 100\right )$% $= 100$%

Multiple choice introduction to ratio and percentages comparing quantities maths

What is the percent profit earned by the shopkeeper on selling the articles in his shop?
I. Labeled price of the article sold was $130$% of the cost price.
II. Cost price of each article was $Rs. 550$.
III. A discount of $10$% on labeled price was offered.

  1. Only I

  2. Only II

  3. I and III

  4. All the three are required

  5. Question cannot be answer even with information in all the three statements.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

I. Let C.P. be $Rs. x$.
Then, $M.P. = 130$% of $x = Rs. \left (\dfrac {13x}{10}\right )$
III. $S.P. = 90$% of M.P.
Thus, I and III give, $S.P. = Rs. \left (\dfrac {90}{100}\times \dfrac {3x}{10}\right ) = Rs. \left (\dfrac {117x}{100}\right )$
$Gain = Rs. \left (\dfrac {117x}{100} - x\right ) = Rs. \dfrac {17x}{100}$
Thus, from I and III, gain % can be obtained.
Clearly, II is redundant.

Multiple choice mathematics and statistics interest applying compound interest compound interest formula with different successive rate of interest compound interest ( for different time period)

Read the following statement carefully and select the correct option 
statement - i : An article marked at rs 800 is sold at successive discount of 15% and 25%. If the buyer desires to sell. it off at a profit of 20% after allowing a 10% discount, then his marked price will be rs 680.
Statement- ii; if the amount of Rs p at 10% per annum for 3 year compounded annually becomes rs q, then q ; p is 125 ; 216.

  1. Both statement- i and statement- ii are false

  2. Both statement- i and statement- ii are true

  3. Both statement- 1 is true but statement- 11 are false

  4. statement - 1 is false but statement -11 is true
Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice maths ratio, proportion and unitary method more on proportion terms related to proportion proportion

A dishonest milkman professes to sell his milk at cost price but he mixes it with water and thereby gains $25$%. The percentage of water in the mixture is

  1. $4$%
  2. $6\frac { 1 }{ 4 } $%
  3. $20$%
  4. $25$%
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

According to the question,

Let's assume milkman has $100$ liter of milk, If he added $x$ liter of water, the percentage of water in the mixture$=\dfrac {x}{(100+x)}\times 100$

The milk gain $25$%, he must have added $25$ liter water in $100$ liter of milk. Then the percentage of water in the mixture$=\dfrac {25}{(100+25)}\times 100=20\%$


In the new mixture, If the milk is $80$% then $80$% of total mixture should be $100$ liter
$(100+x)\times \dfrac{80}{100}=100$
$8x=200$
$x=25$

Then, the percentage of water in the mixture $=\dfrac {25}{(100+25)}\times 100=20\%$

Multiple choice maths money math different discounts successive discounts problems on discounts

Choose the most appropriate option.
A shop gives $15\%$ discount on the purchase of a T.V. If paid for in cash immediately, a further discount of $12\%$ is given. If the marked price is Rs. $15,000$, what is the price of the T.V if cash purchase is made?

  1. Rs. $12,750$
  2. Rs. $11,220$
  3. Rs. $10,950$
  4. Rs. $11,475$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The marked price of T.V. $=Rs.15,000$ 

Price of T.V after $15\%$ discount $=Rs.\left(15,000-\dfrac{15}{100}\times 15000\right)$

                                                      $=Rs.\left(15,000-2250\right)$
                                                      $=Rs.12,750$
Price of T.V. again after $12\%$ discount $=Rs\left(12,750-\dfrac{12}{100}\times 12750\right)$

                                                               $=Rs.\left(12750-1530\right)$
                                                               $=Rs.11,220$

$\therefore$  The price of the T.V if cash purchase is made is $Rs.11,220.$

Multiple choice maths money math different discounts successive discounts problems on discounts

Find the single discount which is equivalent to three successive discounts of 20%, 10% and 5%.
Hence, find the selling price of an article marked at Rs. 250. 

  1. 31.6%; Rs. 171

  2. 31.8%; Rs. 171

  3. 31.6%; Rs. 178

  4. 31.6%; Rs. 71
Reveal answer Fill a bubble to check yourself
A,B Correct answer
Explanation

Given marked price is Rs 250
Selling price after Ist discount =100-20=80 Rs
Selling price after 1st discount=$\frac{80\times 250}{100}= 200$Rs
Selling price after 2nd discount=Selling price after 2nd discount=$\frac{90\times 200}{100}= 180$Rs
Selling price after third discount=$\frac{95\times 280}{100}= 171$Rs
Total discount = 250-171=79 Rs
% of total discuont =Selling price after 2nd discount=$\frac{79\times 100}{250}= 31.6$%

Multiple choice maths money math different discounts successive discounts problems on discounts

Successive discounts of $12\dfrac {1}{2}$% and $7\dfrac {1}{2}$% are given on the marked price of a cupboard. If the customer pays $Rs. 2,590$, then what is the marked price?

  1. $Rs. 3,108$
  2. $Rs. 3,148$
  3. $Rs. 3,200$
  4. $Rs. 3,600$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the marked price be $Rs. 100$
Price after $1st$ discount $= Rs. 87\dfrac {1}{2}$
Price after $2nd$ discount $= Rs. 87\dfrac {1}{2} - 7 \dfrac {1}{2}$% of $87\dfrac {1}{2}$
$\therefore$ Customer pays $= 92\dfrac {1}{2}$% of $Rs. 87\dfrac {1}{2}$
When the customers pay $Rs. 2590$, then the marked price
$= \dfrac {2590\times 100}{92\dfrac {1}{2} \times 87\dfrac {1}{2}} = Rs. 3,200$.

Multiple choice maths money math different discounts successive discounts problems on discounts

A shopkeeper marked his price for $Rs. 150$. He pays a customer $10$% discount and second discount $5$%. What does he get?

  1. $Rs. 122.50$
  2. $Rs. 125$
  3. $Rs. 128.25$
  4. $Rs. 172.50$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Marked price$=Rs.\ 150$

First discount$=10\%$
Hence, price after first discount$=150-\dfrac{10}{100}\times 150=150-15=Rs.\ 135$.
Now, second discount$=5\%$
Hence, price after second discount$=135-5\%\ of\ 135=135-6.75=Rs.\ 128.25$
So, he get $Rs.\ 128.25$

Multiple choice maths money math different discounts successive discounts problems on discounts

After getting three equal successive discounts percentages over a marked price of Rs. $1000$ a customer has to pay $729$ for an article. What is the rate of each of the successive discounts ?

  1. $5$%
  2. $10$%
  3. $15$%
  4. $20$%
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the discount price be$x$.

After the first discount, price$=(1-x)1000$
After the second discount, price$=(1-x)(1-x)1000=(1-x)^21000$
After the third discount, price$=(1-x)(1-x)(1-x)1000=(1-x)^3 1000$
According to the question 
$(1-x)^3 1000=729\(1-x)^3=729/1000\(1-x)=9/10\x=1/10$
Required percentage is $(1/10)\times 100=10\%$.

Multiple choice maths money math different discounts successive discounts problems on discounts

The price of a VCR is marked as $Rs12000$. If successive discounts of $15\%$, $10\%$ and $5\%$ be allowed, then at what price does a customer buy it?

  1. $Rs.\ 8400$
  2. $Rs.\ 8721$
  3. $Rs.\ 8856$
  4. $None\ of\ these$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The marked price of VCR is $Rs.12000.$


Selling price = $85\%$ of $90\%$ of $95\%$ of $Rs.12000$

Selling price = $\dfrac{85}{100}\times \dfrac{90}{100}\times \dfrac{95}{100}\times 12000$

$\therefore$  Selling price $=Rs.8721$

$\therefore$  The price of VCR a customer buy is $Rs.8721.$

Multiple choice maths money math different discounts successive discounts problems on discounts

A shopkeeper allows two successive discounts of 10% and 15% on his articles. If he gets Rs. 459 for an article, find it, marked price.

  1. Rs. $120$
  2. Rs. $300$
  3. Rs. $600$
  4. Rs. $800$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the Marked price be $ x $
After $ 10 $ % discount, the Selling price becomes $ 0.9 x$
After further $ 15 $ % discount, the selling price becomes $ 0.85 \times 0.9x = 0.765x $

Given, SP $ = Rs 459 $
$ => 0.765 = Rs 459 $
$ => x = Rs  600 $

Hence, marked price is $ Rs  600 $

Multiple choice maths money math different discounts successive discounts problems on discounts

A shopkeeper marks the price of an article at Rs. 800. Find the selling price, if he allows three successive discounts of 10%, 5% and 3%.

  1. Rs. 663.48

  2. Rs. 663.40

  3. Rs 663.28

  4. Rs 663.30
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Marked Price of an article=Rs 800.
Price after 1st discount $=$ Rs $800-\cfrac { 10 }{ 100 } \times 800$
$=$Rs $720$
Price after 2nd discount $=$ Rs $720-\cfrac { 5 }{ 100 } \times 720$
$=$Rs $684$
Price after 3rd discount $=$ Rs $684-\cfrac { 3 }{ 100 } \times 684$
$=$ Rs $663.48$
Selling Price after three successive discounts $=$ Rs$ 663.48$

Multiple choice maths money math different discounts successive discounts problems on discounts

The marked price of an article is Rs. $500$. It is sold at successive discounts of $20\%$ and $10\%$. The selling price of the article (in Rs.) is

  1. $350$
  2. $375$
  3. $360$
  4. $400$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

M.P. $=$ Rs. $500$, $1^{st}$ discount $ = 20\%$
Net price after $1^{st}$ discount $= 80\%$ of Rs. $500=\dfrac {80}{100}\times 500=$ Rs. $400$
$2^{nd}$ discount $= 10\%$
$\therefore$ Final S.P. after $2^{nd}$ discount $=\dfrac {90}{100}\times 400$
$=$ Rs. $360$