Probability Questions

Multiple choice
  1. 1/(50 × 49 × 48 × 47 × 46 × 45 × 10)

  2. (1 × 6)/(50 × 49 × 48 × 47 × 46 × 45 × 10)

  3. (10 × 6)/(50 × 49 × 48 × 47 × 46 × 45 × 10)

  4. (50 × 6)/(50 × 49 × 48 × 47 × 46 × 45 × 10)

  5. a

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Since the balls must be matched in the exact order they are drawn, the probability of matching the first ball is 1/50, the second is 1/49, and so on, down to 1/45 for the sixth ball. The probability of matching the single bonus ball is 1/10, so the combined probability is the product of these individual probabilities.

Multiple choice
  1. 4 C 2 + 48 C 5 52 C 7

  2. 4 C 2 × 48 C 5 52 C 7

  3. 7 C 2 + 48 C 5 52 C 7

  4. 7 C 2 × 48 C 5 52 C 7

  5. a

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Choose exactly 2 of the 4 aces and 5 of the 48 non-aces, then divide by the total number of 7-card hands. The probability is C(4,2) x C(48,5) / C(52,7), corresponding to option B.

Multiple choice
  1. Quantity A is greater.

  2. Quantity B is greater.

  3. The two quantities are equal.

  4. The relationship cannot be determined from the information given.

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The set of values is {-12, -8, -4, 4, 8, 12}. Since the distribution is symmetric around zero, the probability of getting a positive sum is equal to the probability of getting a negative sum. The only case where the sum is zero is when the two dice show additive inverses (e.g., -12 and 12, or 4 and -4).

Multiple choice
  1. 2q= 1 +(2p-1)4

  2. q = l + (2p + 1 ) 4

  3. q = 1 - (2p - 1 )4

  4. 2q = 1 - (2p + 1 )4

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The probability of an even number of heads in n trials is given by (1 + (1-2p)^n)/2. For n=4, this is (1 + (1-2p)^4)/2. Since (1-2p)^4 = (2p-1)^4, the expression becomes (1 + (2p-1)^4)/2, or 2q = 1 + (2p-1)^4.