Multiple choice

A pair of dice is thrown. Find the probability of the numbers appearing whose sum is less than or equal to 6.

  1. 5 12

  2. 5 13

  3. 6 13

  4. 6 17

  5. 7 15
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A Correct answer
Explanation

Total outcomes when throwing two dice are 36. Outcomes with sum <= 6 are: (1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (4,1), (4,2), (5,1). There are 15 such outcomes. Probability = 15/36 = 5/12.

AI explanation

When a pair of dice is thrown, the total number of possible outcomes is 6 times 6, or 36. The combinations that result in a sum less than or equal to 6 are: (1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (4,1), (4,2), and (5,1), giving exactly 15 favorable outcomes. The probability is found by dividing these 15 favorable outcomes by the 36 total outcomes, which simplifies to 5/12.

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