A coin is tossed five times. What is the probability that there is at the least one tail?
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A coin is tossed five times. What is the probability that there is at the least one tail?
31/32
1/16
2/12
1/2
1/32
Probability of at least one tail = 1 - P(no tails). P(no tails) = P(all heads) = (1/2)^5 = 1/32. P(at least one tail) = 1 - 1/32 = 31/32.
Using the complementary event axiom, the probability of getting at least one tail equals one minus the probability of getting zero tails. The only outcome with zero tails in five tosses is getting all heads, which has a probability of (1/2)^5 = 1/32. Therefore, the required probability is 1 - 1/32 = 31/32.