Quantitative Aptitude
Pipes and Cisterns
535 Questions
Pipes and Cisterns Questions
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$3 m$
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$-3 m$
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$6 m$
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$-6 m$
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$76$ min
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$80$ min
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$90$ min
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$96$ min
D
Correct answer
Explanation
Volume of water needed = 200 * 150 * 2 = 60000 m^3. Pipe cross-section = 1.5 * 1.25 = 1.875 m^2. Speed of water = 20000 m/hr. Volume per hour = 1.875 * 20000 = 37500 m^3/hr. Time = 60000 / 37500 = 1.6 hours = 96 minutes.
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$\displaystyle \sqrt{2}m$
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$2 m$
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$\displaystyle \frac{1}{2}m$
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$\displaystyle \frac{1}{\sqrt{2}}m$
A
Correct answer
Explanation
Volume = Area * Speed * Time. 440 = (pi * r^2) * 7 * 10. 440 = 70 * pi * r^2. r^2 = 440 / (70 * (22/7)) = 440 / 220 = 2. r = sqrt(2).
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5260 L
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5760 L
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5846 L
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6970 L
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$3hr$ $12min$
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$2hr$ $12min$
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$3hr$ $22min$
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None of these
A
Correct answer
Explanation
Volume of tank = pi * r^2 * h = pi * 2^2 * 10 = 40pi. Half volume = 20pi m^3. Pipe flow rate = Area * velocity = pi * (0.05)^2 * 2500 m/hr = pi * 0.0025 * 2500 = 6.25pi m^3/hr. Time = 20pi / 6.25pi = 3.2 hours. 0.2 hours = 12 minutes. Total = 3 hours 12 minutes.
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$2.32 m$
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$2.52 m$
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$2.72 m$
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$2.92 m$
B
Correct answer
Explanation
Volume of water flowing per second = Area of pipe * velocity = pi * (r_pipe)^2 * v. Diameter = 4/3 cm, so radius = 2/3 cm = 2/300 m. Area = pi * (2/300)^2. Volume per hour = Area * 0.63 * 3600. This volume fills the tank to height h: pi * (0.2)^2 * h = Volume per hour. Solving for h gives 2.52 m.
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$9$ min
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$10$ min
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$11$ min
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$12$ min
A
Correct answer
Explanation
Let M and N work for x minutes. N works for an additional 5 minutes. (x/30) + (x+5)/20 = 1. Multiply by 60: 2x + 3(x+5) = 60. 2x + 3x + 15 = 60. 5x = 45. x = 9 minutes.
A
Correct answer
Explanation
Let the rate of A be x. Then B is 3x and C is 2 * 3x = 6x. Combined rate is x + 3x + 6x = 10x. Since they fill the tank in 20 hours, the total work is 10x * 20 = 200x. Pipe A alone takes 200x / x = 200 hours.
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$15$ min
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$20$ min
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$25$ min
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$10$ min
A
Correct answer
Explanation
1/M + 1/N = 1/6. M = N - 5. 1/(N-5) + 1/N = 1/6. (N + N - 5) / (N(N-5)) = 1/6. 6(2N - 5) = N^2 - 5N. 12N - 30 = N^2 - 5N. N^2 - 17N + 30 = 0. (N-15)(N-2) = 0. N = 15.
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$3\displaystyle\frac { 9 }{ 17 }$ hours
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$11$ hours
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$2\displaystyle\frac { 8 }{ 11 }$ hours
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$1\displaystyle\frac { 13 }{ 17 }|$ hours
D
Correct answer
Explanation
Pipe A fills at 1/5 tank/hr, B fills at 1/6 tank/hr, and C empties at 1/12 tank/hr. Net rate = 1/5 + 1/6 - 1/12 = (12 + 10 - 5) / 60 = 17/60 tank/hr. Since the tank is half full initially, the remaining volume to fill is 1/2 tank. Time required = (1/2) / (17/60) = 30/17 = 1 13/17 hours. Note that option D is formatted with a stray pipe symbol due to OCR.
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$30\ km/h$
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$36\ km/h$
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$40\ km/h$
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$None\ of\ these$
A
Correct answer
Explanation
Volume of water in tank = 30 * 20 * 1 = 600 cubic meters. Time = 8 hours. Flow rate = 600 / 8 = 75 cubic meters/hour. Pipe area = 0.05 * 0.05 = 0.0025 square meters. Speed = Flow rate / Area = 75 / 0.0025 = 30000 meters/hour = 30 km/h.
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$5$ hour
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$5\frac{2}{3}$ hours
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4 hours
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$4\frac{2}{3}$ hours
D
Correct answer
Explanation
A fills 1/4 per hour, B fills 1/6 per hour. In 2 hours (one cycle), they fill 1/4 + 1/6 = 5/12. In 4 hours, they fill 10/12 = 5/6. Remaining = 1/6. In the 5th hour, A fills 1/4. Since 1/6 < 1/4, it takes (1/6) / (1/4) = 2/3 hours. Total time = 4 + 2/3 = 4 2/3 hours.
B
Correct answer
Explanation
Rate A = 1/5, Rate B = 1/20. Combined rate = 1/5 + 1/20 = 5/20 = 1/4. Time to fill = 4 hours. With leak, time = 4.5 hours. Combined rate - Leak rate = 1/4.5 = 2/9. Leak rate = 1/4 - 2/9 = (9-8)/36 = 1/36. Leak empties in 36 hours.
B
Correct answer
Explanation
Rate of A = 1/3 tank/hr. Rate of B = 1/2 tank/hr. Combined rate = 1/3 + 1/2 = 5/6 tank/hr. Time to fill 2/3 of the tank = (2/3) / (5/6) = (2/3) * (6/5) = 4/5 hours. 4/5 hours = 48 minutes.