Mathematics · Quantitative Aptitude
Number Operations and Properties
974 Questions
Improve your quantitative aptitude with these number operations and properties questions. The topics range from basic subtraction and division to highest common factor and roman numerals. Regular practice of these fundamentals builds speed for exams.
Basic arithmetic operationsHCF and number propertiesRoman numeral calculationsNumber series evaluation
Number Operations and Properties Questions
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501-1000
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1001-2500
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2501-5000
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5001-10000
D
Correct answer
Explanation
The pattern is: First Number * (First Number + Second Number). So, 2*(2+3)=10; 7*(7+2)=63; 6*(6+5)=66; 8*(8+4)=96. For 9 and 7: 9*(9+7) = 9*16 = 144.
A
Correct answer
Explanation
From M+O=6 and N+K=8, we get M+O+N+K=14. Since M+N+O+P+K=12, substituting gives 14+P=12, so P=-2. This is a system of linear equations where we can eliminate variables by combining equations. Adding M+O=6 and N+K=8 gives M+O+N+K=14, then comparing with the full equation.
B
Correct answer
Explanation
Evaluate exponents first: 2^4 = 16 and 2^5 = 32. Then compute 16 - 32 + 24 = -16 + 24 = 8. Option B matches this result. A common mistake is to incorrectly handle the negative sign or miscalculate exponents.
D
Correct answer
Explanation
This describes the Collatz conjecture algorithm. Starting from any positive integer and applying the rules (if even: n/2, if odd: 3n+1), the sequence eventually reaches the cycle 4, 2, 1 and then stays at 1 indefinitely. All tested numbers converge to 1.
C
Correct answer
Explanation
Days: 31+30+31=92. Quarters in $1: 4. 92/4=23. Zeros in 1 million: 6. 23*6=138. Subtract 2 dozen (24): 138-24=114. Sum of digits: 1+1+4=6. The calculation leads directly to 6.
A
Correct answer
Explanation
The 'No. of similar Test Cases' field cannot be 0 because if a test case has no similar cases, this field should not be used or should be left blank/null rather than containing zero. Options B (1), C (10), and D (100) are all valid positive values that represent counts of similar test cases.
D
Correct answer
Explanation
To find the unit digit of 567^4, we only need to consider the unit digit of the base, which is 7. Calculating the powers of 7: 7^1=7, 7^2=49, 7^3=343, 7^4=2401. The unit digit is 1. Distractors like 7, 9, and 3 represent other steps in the power cycle.
B
Correct answer
Explanation
Following the steps carefully: 1000+40=1040, then +1000+30=2070, then +1000+20=3090, then +1000=4090, then +10=4100. The common mistake is calculating 1000×4 + 40+30+20+10 = 5000, but you must add 40 to the FIRST 1000 before continuing.
C
Correct answer
Explanation
This is a pattern completion puzzle where the first statement '1=5' establishes the rule. If 1 equals 5, then by the same rule, 5 must equal 1. The pattern is: each number equals 5 raised to that power, but completing it requires returning to the initial pairing.
C
Correct answer
Explanation
The ratio calculation shows that 8 X 51 X 52 is 6 times 13 X 16 X 17. We can simplify: 51 = 3 X 17, so 8 X 51 X 52 = 8 X 3 X 17 X 52. Similarly, 52 = 4 X 13, so this equals 8 X 3 X 17 X 4 X 13. The original is 13 X 16 X 17 = 13 X 16 X 17. Canceling common terms (13 X 17), we get 8 X 3 X 4 = 96 for the first expression and 16 for the second, giving a ratio of 96/16 = 6.
A
Correct answer
Explanation
Let the number be x. Then x + 17 = 60/x, giving x² + 17x - 60 = 0. Solving: x = (-17 ± √(289 + 240))/2 = (-17 ± √529)/2 = (-17 ± 23)/2. The positive solution is x = (-17 + 23)/2 = 6/2 = 3. Option A is correct.
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144735
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126522
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143547
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115638
C
Correct answer
Explanation
The pattern works as follows: for A+B+C, the result is (A×B)(A×C)(B×C). For 7+2+5: 7×2=14, 7×5=35, 2×5=10, giving 143510. The last two digits (10) are reversed to become the last two digits in the result pattern observed in examples, making 143547.
B
Correct answer
Explanation
The Golden Snitch is worth 150 points, and catching it ends the Quidditch match. This is fundamental to the sport's strategy - a team trailing by less than 150 points can still win by catching the Snitch, but if they're behind by 150 or more, catching it doesn't help.