Number Operations and Properties

Following order of operations (PEMDAS/BODMAS), multiply first: 5*5 = 25, then add: 25+6 = 31, which is option B. Option A (55) incorrectly treats this as concatenation. Option C (16) incorrectly does 5*5=25, then 2+5=7, then 7+6=13 (not 16 anyway). Option D is nonsensical.

Using order of operations (PEMDAS/BODMAS): Calculate from left to right, handling multiplication and division first: 2×5 = 10, then 6÷3 = 2, then 2×10 = 20. Finally: 10 - 20 + 20 = 10. The division and multiplication happen before the final addition and subtraction.

This is a wordplay riddle. Grammatically, you can only subtract 5 from 25 once - after that, you're subtracting from 20, 15, 10, or 5. The question asks 'how many times' (frequency), not 'how many times repeatedly'. 'None of these' is correct because options 5, 3, and 0 all miss the linguistic trick.

If 1+1=2 is 'wrong', then basic arithmetic is invalid. Following this premise, 9+2=11 would also be wrong. Option D '11 is wrong' correctly identifies that the answer 11 is incorrect under the premise that standard addition is wrong.

In the cryptarithm SEND + MORE = MONEY, each letter represents a unique digit (0-9). Solving the column addition from right to left: D+E=Y (with possible carry), N+R=E (with carry), E+O=N (with carry), S+M=M (which means S=9 with carry). The unique solution is S=9, E=5, N=6, D=7, M=1, O=0, R=8, Y=2, giving SEND=9567, MORE=1085, and MONEY=10652.

This is a trick question - you can subtract 5 from 25 only once, because after one subtraction you have 20, not 25. The question specifically asks about subtracting from 25.

This is a mental math trick question. 1000+40+1000+30+1000+20+1000+10 = 4100. The riddle relies on people mistakenly grouping as thousands and getting 5000.

Sn has terms 3, 8, 15, 24, 35... where the k-th term is k²+2k. S20 = sum from k=1 to 20 of (k²+2k) = 2870 + 420 = 3290. S'n has terms 6, 11, 18, 27... where the k-th term is k²+2k+3. S'20 = sum from k=1 to 20 of (k²+2k+3) = 2870 + 420 + 60 = 3350. Therefore S20 - S'20 = 3290 - 3350 = -60.

Let the number be x. When multiplied by 13, it becomes 13x. The statement 'becomes greater to 105 by an amount with which it is lesser to 105 by now' means: the excess over 105 after multiplication equals the deficit before multiplication. So 13x - 105 = 105 - x, which gives 14x = 210, so x = 15. Indeed, 15 is 90 less than 105, and 195 (15×13) is 90 more than 105.

Let the number be x. 'Multiplied by 13, becomes greater to 105 by an amount with which it is lesser to 105 by now' translates to: 13x = 105 + (105 - x). Simplifying: 13x = 210 - x → 14x = 210 → x = 15. Verify: 15 is 90 less than 105. When multiplied by 13, 195 becomes 90 greater than 105. The condition holds.

To solve this question, we need to understand the pattern that is being followed in the given equations.

Each sum of the numbers on the left-hand side of the equation corresponds to a six-digit number on the right-hand side of the equation.

Let's break down the first equation:

• 5 + 3 + 2 = 10
• The corresponding six-digit number is 151012.

Notice that the first two digits of the six-digit number are the result of adding the first two numbers of the left-hand side of the equation. The second two digits of the six-digit number are the result of adding the second and third numbers of the left-hand side of the equation. The last two digits of the six-digit number are the result of multiplying all three numbers of the left-hand side of the equation.

Using this pattern, we can solve the given question:

• 7 + 2 + 5 = 14
• The corresponding six-digit number is 143542.

Therefore, the answer is:

The Answer is: C. 143542

This is a lateral thinking puzzle. You can only subtract the number 5 FROM 25 exactly once. After subtracting once (25 - 5 = 20), you're subtracting from 20, not from 25 anymore. The question is phrased precisely to ask about subtracting 'from 25', not about how many times 5 can be subtracted repeatedly.

When adding a positive number to a negative number, you subtract the smaller absolute value from the larger one and keep the sign of the larger absolute value. Here, 14 - 4 = 10, and since -14 has the larger magnitude, the result is -10.