Mensuration Questions

Multiple choice
  1. 154

  2. 308

  3. 269.5

  4. 370

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total surface area = 231 cm², curved surface area = (2/3) × 231 = 154 cm². This means the area of the two circular bases is 231 - 154 = 77 cm². So 2πr² = 77, giving r² = 77/(2π). Curved surface area = 2πrh = 154. Substituting r, we get h = 154/(2πr). Volume = πr²h = πr² × 154/(2πr) = 77r. Using r = √(77/(2π)), volume ≈ 77 × 3.5 = 269.5 cm³.

Multiple choice
  1. $2154.25π$
  2. $2456.25π$
  3. $2526.75π$
  4. $2080.75π$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The total surface area of a hollow hemispherical vessel includes the inner curved surface (2πr²), outer curved surface (2πR²), and the area of the circular ring at the top (π(R² - r²)). With inner radius r = 24 cm and outer radius R = 25.5 cm, the sum is 1152π + 1300.5π + 74.25π = 2526.75π cm². Option A (2154.25π) incorrectly omits the ring area, while Option D (2080.75π) uses incorrect radius measurements.

Multiple choice
  1. 362

  2. 352

  3. 416

  4. 516

  5. None of these इनमें से कोई नहीं

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Volume of cylinder = π × 14² × 196 = π × 196 × 196 = 38416π cm³. Volume of one cube = 7³ = 343 cm³. Number of cubes n = 38416π/343 = 112π = 352 (since π is taken as 22/7). The cylinder volume is exactly converted to cube volumes.

Multiple choice
  1. 6 minutes

  2. 5 minutes

  3. 10 minutes

  4. 9 minutes

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

First calculate the pipe's cross-sectional area: π × 7² = 49π cm². The flow rate per second is 49π × 500 = 24500π cm³/s. The tank volume is 3 × 5 × 1.54 = 23.1 m³ = 23,100,000 cm³. Time = 23,100,000 ÷ (24500π) ≈ 300 seconds = 5 minutes. This is a practical application of volume flow rate calculation.

Multiple choice
  1. $\(\frac{15625}{6}\pi\)$
  2. $\(\frac{35937}{8}\pi\)$
  3. $\(\frac{11979}{2}\pi\)$
  4. $\(\frac{15625}{8}\pi\)$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Surface area of sphere = 4πr². When radius increases by 4cm, the difference in surface area is 4π[(r+4)² - r²] = 4π(8r + 16) = 464π. Solving: 8r + 16 = 116, so r = 12.5cm. Original volume = (4/3)π(12.5)³ = (4/3)π(1953.125) = 7812.5/3 π = 15625/6 π. Option A matches this value.

Multiple choice
  1. 4

  2. 1

  3. 6

  4. 28

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Cone volume = (1/3)π(7)²(28) = (1/3)π(49)(28) = (1372/3)π cm³. Sphere volume = (4/3)π(7)³ = (4/3)π(343) = (1372/3)π cm³. Since volumes are equal, only 1 sphere can be formed. Option A (4) incorrectly divides volume by 4. Option C (6) is arbitrary. Option D (28) confuses radius with number of spheres.

Multiple choice
  1. 25%

  2. 26%

  3. 40%

  4. 36%

  5. 52%

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Volume of cylinder = πr²h. If radius increases by 25%, new radius = 1.25r, so new radius factor = 1.25² = 1.5625. To keep volume constant: πr²h = π(1.25r)²(h_new) = π × 1.5625r² × h_new. Therefore h_new = h/1.5625 = 0.64h. The height decreases by 1 - 0.64 = 0.36 = 36%. The answer 36% is correct.

Multiple choice
  1. 905.14

  2. 1024.6

  3. 816

  4. 765

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The maximum volume of a sphere is (4/3)πr³. For a sphere of radius 6 cm, the volume is (4/3)π(216) = 288π ≈ 904.78 cm³, which rounds to 905.14 cm³. The cube side (12+4√3) cm provides enough space to accommodate two such spheres through optimal arrangement.

Multiple choice
  1. Either statement III alone or statements I and II together are sufficient.

  2. Only statement III is sufficient.

  3. Only statement I and III is sufficient.

  4. Statement I, II, and III together are sufficient.

  5. None of these

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

We need all three statements: From II, perimeter = 50, so 2(l+b)=50, l+b=25. From I, l-b=5. Solving: l=(25+5)/2=15, b=(25-5)/2=10. Area = 15×10=150 sq.cm. From III, cost of 100 sq.cm is 1000, so rate = 1000/100=10 per sq.cm. Total cost = 150×10=1500. All three statements together are necessary and sufficient.

Multiple choice
  1. Quantity I > Quantity II

  2. Quantity I ≥ Quantity II

  3. Quantity I <Quantity II

  4. Quantity II ≥ Quantity I

  5. Quantity I = Quantity II or relation can't be established

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Quantity I: For equilateral triangle with altitude 3√3 cm, side = 2×3√3/√3 = 6 cm, Area = (√3/4)×6² = 9√3 ≈ 15.59 cm². Quantity II: Circle with radius 3.5 cm has Area = π×3.5² = 12.25π ≈ 38.50 cm². Since 15.59 < 38.50, Quantity I is less than Quantity II.

Multiple choice
  1. 660

  2. 612

  3. 675

  4. 624

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Curved surface area of cylinder = 2πrh. Given diameter = 70 cm, so radius = 35 cm = 0.35 m. Height = 6 m. CSA = 2 × (22/7) × 0.35 × 6 = 2 × 22 × 0.05 × 6 = 13.2 m². Cost at Rs. 50 per m² = 13.2 × 50 = Rs. 660.

Multiple choice
  1. 868 cm2

  2. 850 cm2

  3. 890 cm2

  4. 880 cm2

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

For a cone with height h = 42 cm and diameter d = 13 cm (radius r = 6.5 cm). Curved surface area = πrl, where l = √(h² + r²) = √(42² + 6.5²) = √(1764 + 42.25) = √1806.25 ≈ 42.5 cm. CSA = π × 6.5 × 42.5 ≈ 3.14 × 6.5 × 42.5 ≈ 868 cm². Option A (868) is the approximate curved surface area.