Multiple choice

What is the volume of the frustum in cm$^3$ of the cone of height 7cm and bigger radius and smaller radius be 10cm and 5cm respectively? (Take $\pi = \frac{22}{7}$)

  1. $1283\frac{1}{3}$
  2. $1478\frac{1}{3}$
  3. $1283\frac{2}{3}$
  4. $1478\frac{2}{3}$
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A Correct answer
Explanation

Volume of frustum = (1/3)πh(R² + Rr + r²). Given h = 7cm, R = 10cm, r = 5cm: V = (1/3) × (22/7) × 7 × (100 + 50 + 25) = (22/3) × 175 = 3850/3 = 1283⅓ cm³.

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