Physics
Gravitation and Center of Mass
368 Questions
Gravitation and center of mass questions explore gravitational fields, planetary density, and the mechanics of celestial bodies. Test items include calculating gravitational strength on different planets and understanding the Roche Limit. This topic is essential for the physics syllabus of major competitive exams.
Gravitational fieldCenter of massPlanetary densityHill SphereSpace-time curvature
Gravitation and Center of Mass Questions
-
at the equator
-
at the North Pole
-
at the South Pole
-
at the centre of the earth
D
Correct answer
Explanation
Weight is defined as the force of gravity on an object. At the center of the Earth, the gravitational pull from all directions cancels out, resulting in zero weight.
-
The North Pole
-
The South Pole
-
The Equator
-
The center of the Earth
D
Correct answer
Explanation
Weight is the force of gravity acting on an object. At the center of the Earth, the gravitational pull from all directions cancels out, making the effective weight of an object zero (the minimum possible).
-
a point
-
both scaler and vector
-
scalar
-
vector
A
Correct answer
Explanation
Centre of mass of a body is the point at which whole mass of the body is concentrated
-
poles
-
equator
-
centre of Earth
-
tropics
C
Correct answer
Explanation
At the center of the Earth, the gravitational pull from all directions cancels out, resulting in a net gravitational acceleration of zero. At the poles and equator, gravity is present, though it varies slightly due to the Earth's rotation and shape.
-
increased
-
neutralised
-
decreased
-
the same
B
Correct answer
Explanation
Weight is the force of gravity on an object. At the center of the Earth, the gravitational pull from all directions cancels out, resulting in zero weight.
-
At the equator
-
At the center of the earth
-
At the north pole
-
None of these
B
Correct answer
Explanation
Weight is the force exerted by gravity on an object. At the center of the Earth, the gravitational pull from all directions cancels out, resulting in zero weight.
-
100 N
-
200 N
-
300 N
-
400 N
-
None of these
B
Correct answer
Explanation
The gravity on the moon is approximately 1/6th of the gravity on Earth. Therefore, 1200 N / 6 = 200 N.
-
1/5 times that of earth
-
2/5 times that of earth
-
3/5 times that of earth
-
4/5 times that of earth
D
Correct answer
Explanation
The mass of venus is 4/5 times that of earth
-
the same as on the earth
-
less than on the earth as the moon has a smaller mass
-
there is no gravitational force at all
-
more than the earth
B
Correct answer
Explanation
The gravitational acceleration on the surface of the Moon is 1.63 m/s2, about 16.7% that on Earth's surface.
-
on other planets
-
on all bodies
-
only on moon
-
only on human beings
B
Correct answer
Explanation
Gravitational force is acting on all bodies containing mass.
-
There is less force of gravity on moon.
-
There is no atmosphere on moon.
-
Moon is farther away from Sun.
-
Moon has more gravitational force.
A
Correct answer
Explanation
Yes, it is correct. Moon's gravitational force is lesser than that of earth. The mass remains unchanged but the weight changes which depends on gravitational force.
-
318 M
-
1000 M
-
1300 M
-
1400 M
A
Correct answer
Explanation
Mass of Jupiter is about 318 times that of Earth.
D
Correct answer
Explanation
Since gravitational force is inversely proportional to the square of distance between the particles/bodies and according to given conditions of question, the distance between two body is now three times more than before, hence it is F/(3*3).
-
(2/9)Gπ2D2a4
-
(4/7)Gπ2D2a4
-
(4/9) Gπ2D2a4
-
(2/7) Gπ2D2a4
C
Correct answer
Explanation
m, a m, a
Here, F = G mm/(2a)2 = Gm2/4a4 = G/4a2 × (D × 4/3 × πa3)2 = (4/9)Gπ2D2a4
-
3.38 cm/s2
-
4.45 cm/s2
-
3.0 cm/s2
-
5.55 cm/s2
A
Correct answer
Explanation
Effective acceleration due to gravity is given by, g’ = g-Rω2 cos2Ө.
Hence, change in acceleration due to gravity is given as, ∆g = g’-g = - Rω2 cos2Ө
At equator Ө = 0.
Hence, g’-g = -R ω2 = -6.4×106× (7.27×10-5)2
= -0.0338 m/s2
Or, g’-g = -3.38 cm/s2
The (-) ve sign signifies that the decrease in gravitational acceleration is due to the rotation of earth.