Physics

Gravitation and Center of Mass

368 Questions

Gravitation and center of mass questions explore gravitational fields, planetary density, and the mechanics of celestial bodies. Test items include calculating gravitational strength on different planets and understanding the Roche Limit. This topic is essential for the physics syllabus of major competitive exams.

Gravitational fieldCenter of massPlanetary densityHill SphereSpace-time curvature

Gravitation and Center of Mass Questions

Multiple choice
  1. decreases

  2. increases

  3. remains the same

  4. none of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Acceleration due to gravity (g) decreases with altitude because g = GM/r², where r is the distance from Earth's center. As altitude increases, r increases, causing g to decrease. This is why objects weigh slightly less at higher altitudes.

Multiple choice
  1. at the equator

  2. at the poles

  3. at the centre

  4. in the space

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Weight (mg) is more at the poles because g is maximum at the poles and minimum at the equator. This happens because: (1) Earth is not a perfect sphere - it's flattened at poles (polar radius < equatorial radius), so you're closer to Earth's center at poles, and (2) centrifugal force at equator slightly reduces effective g.

Multiple choice
  1. 2 kg

  2. 6 kg

  3. 12 kg

  4. 24 kg

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Weight on the moon is approximately 1/6th of weight on Earth because moon's gravitational acceleration (g_moon ≈ 1.62 m/s²) is about 1/6th of Earth's (g_earth ≈ 9.81 m/s²). A 12 kg weight on Earth would weigh approximately 12 × (1/6) = 2 kg on the moon. Note: the question uses 'kg' for weight when it should use 'N' for force - mass (12 kg) remains constant.

Multiple choice
  1. 980 ms-2

  2. 98 ms-2

  3. 9.8 ms-2

  4. 0.98 ms-2

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The acceleration due to gravity (g) at Earth's surface is approximately 9.8 m/s². This is the maximum value because g decreases with increasing altitude or depth from the surface. Option A (980) would be in cm/s², not m/s². Option B (98) and D (0.98) are incorrect values.

Multiple choice
  1. maximum

  2. the same as that at the surface

  3. zero

  4. minimum

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

At Earth's center, a body is equidistant from all surrounding mass. Gravitational forces from all directions cancel out completely, resulting in zero net gravitational force and thus g = 0. Option A is incorrect because g is maximum at the surface, not the center. Option B is wrong since g varies with depth. Option D is misleading - g is zero, not just minimum.

Multiple choice
  1. a scalar quantity

  2. a vector quantity

  3. neither scalar nor vector

  4. zero

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

A gravitational field has both magnitude and direction - it points toward the mass creating the field. This makes it a vector quantity. Options A and C are incorrect because the field definitely has direction. Option D is wrong because the field strength is non-zero (it's g at that point).

Multiple choice
  1. at the north pole

  2. at the south pole

  3. at the equator

  4. at the centre of the earth

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Weight is minimum (zero) at Earth's center because gravitational forces from all surrounding mass cancel completely. At the poles (A and B), weight is maximum due to no centrifugal reduction. At the equator (C), weight is slightly less than at poles due to centrifugal force from Earth's rotation, but still much more than zero at the center.

Multiple choice
  1. both a and b

  2. both b and c

  3. a, b and c

  4. b, c and d

  5. a, b and d

Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Yes, it is the correct answer, as all the three statements mention the importance of the Universal Law of Gravitation.

Multiple choice
  1. M decreased and W was constant

  2. M decreased and W increased

  3. M was constant and W increased

  4. M was constant and W decreased

  5. M increased and W was constant

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Yes, it is the correct answer. Mass will remain the same whether that object is on the moon, on the earth or anywhere in the universe. Weight of an object on the earth is the force by which earth attracts that very object towards it, which becomes less on moon.

Multiple choice
  1. a

  2. b

  3. c

  4. d

  5. e

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Yes, it is correct as this shows the maximum force of attraction between A and B. F = G x M x m / D x DF = G x 27.3 N

Multiple choice
  1. 6 × 1022 kg

  2. 6 × 1023 kg

  3. 6 × 1024 kg

  4. 6 × 1020 kg

  5. 6 × 1021 kg

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

As we know that, F = GMm/ R2.
Where G = Gravitational constant, M = mass of the earth, m = mass of the another body at the surface of the earth, R = Radius of the earthor, F= ma ( here a = g) ma = GMm/ R2 Or M = g, R2/ GOr M = 9.8 (6.4×106)2 / 6.67 × 10 – 11 = 6× 1024 kg. It is the correct option

Multiple choice
  1. G is the acceleration due to gravity and g is the Universal Gravitation Constant

  2. G is the Universal Gravitation Constant and g is the acceleration due to gravity

  3. Both G and g are the acceleration due to gravity

  4. Both G and g are the Universal Gravitation Constant

  5. Both 1 and 2 are correct

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

G is numerically equal to the force of attraction between two unit mass, placed at a unit distance. It is denoted by G, the acceleration produced in the motion of body under the effect of gravity is called acceleration due to gravity. It is denoted by g, so it is the correct option.