Geography · Physics
Geodesy and Celestial Mechanics
1,049 Questions
Geodesy and celestial mechanics questions explore Earth measurements, great circles, and planetary motions. These concepts form a crucial part of physical geography and astronomy in competitive exams. Practice these questions to grasp longitudinal and latitudinal calculations.
Longitude and latitude calculationsGreat circle conceptEarths axial precessionLagrangian pointsAtmosphere boundary
Geodesy and Celestial Mechanics Questions
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Distance from the poles
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Angles from the equator
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Angles from the poles
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None of these
B
Correct answer
Explanation
Latitude is defined as the angular distance of a point north or south of the equator, measured in degrees.
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23°-52' N. to 30°-28' N. Lat. and 77°-3' E. to 82°-42' E. long
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22°-56' N. to 32°-22' N. lat. and 75°-27' E. to 82°-42' E. long
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28°-24'-17 N. to 28°-53'-00 N. lat. and 76°-50'-24 E. to 77°-20'-37 E. long
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<span style="font-family:" arial;="" font-size:="" small;="">25°-24'-17 N. to 25°-53'-00 N. lat. and 72°-50'-24 E. to 74°-20'-37 E. long
C
Correct answer
Explanation
The coordinates 28 degrees 24 minutes 17 seconds N to 28 degrees 53 minutes 00 seconds N latitude and 76 degrees 50 minutes 24 seconds E to 77 degrees 20 minutes 37 seconds E longitude accurately define the geographical extent of Delhi.
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Oblate spheroid
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True sphere
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Oval
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Round
A
Correct answer
Explanation
The Earth is not a perfect sphere; due to its rotation, it bulges at the equator and is flattened at the poles, making its shape an oblate spheroid.
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450 million km
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250 million km
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150 million km
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14 million km
C
Correct answer
Explanation
The average distance from the Earth to the Sun is approximately 149.6 million kilometers, which is commonly rounded to 150 million km.
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384,400 Kms
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225 million Kms
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261 million Kms
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300 Kms
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30 Kms
A
Correct answer
Explanation
This is the distance of the Moon from the Earth.
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49th parallel
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38th parallel
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45th parallel
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40th parallel
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None
A
Correct answer
Explanation
The 49th parallel north is the circle of latitude that forms the international boundary between the United States and Canada.
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Half an hour
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Forty-five minute
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One hour
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One hour and fifteen minute
C
Correct answer
Explanation
The Earth rotates 360 degrees in 24 hours. Therefore, 360/24 = 15 degrees per hour.
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64 min
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34 min
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84 min
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120 min
C
Correct answer
Explanation
Fcentripetal = Fgravitation
mω2R = mg or, ω = √ (g/R) or, T = 2π√(R/g)
Since g = 9.8 m/s2 and r = R = 6.4×106 (radius of the earth)
Now, T = 2π√(R/g) = 2π√ (6.4×106/9.8) = 84 min (approx.)
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339, 298
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893, 289
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393, 298
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2-3-1-4
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1-4-2-3
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2-4-1-3
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1-3-2-4
C
Correct answer
Explanation
In the idealized tricellular circulations, the sequence of pressure conditions from equator to poles is (i) Equatorial low, (ii) Subtropical high, (iii) Subpolar low, (iv) Polar high. The equatorial low pressure belt is located on either side of the geographical equator in a zone extending between 5°N and 5°S latitudes but this zone is not stationary because there is seasonal shift of belt. Subtropical high pressure belt extends between the latitude of 25°-35° in both the hemisphere. It is important to note that this high pressure belt is not thermally induced because this zone besides two to three winter months receives fairly high temperature throughout the year. Each polar low pressure belt is located between 60°- 65° latitudes in both the hemisphere. Polar high pressure belt persists at the poles throughout the year because of prevalence of very low temperature below freezing point all the year round.
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Both I and II
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I only
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II only
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Neither I nor II
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always subtractive
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always zero
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always additive
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dependent on latitude
The observations from a closed loop traverse around an obstacle are as follows
|
|
|
|
| Segment |
Observation from station |
Length (m) |
Azimuth (clockwise from magnetic north) |
| PQ |
P |
Missing |
33.7500o |
| QR |
Q |
300.000 |
86.3847o |
| RS |
R |
354.524 |
169.3819o |
| ST |
S |
450.000 |
243.9003o |
| TP |
T |
268.000 |
317.5000o |
What is the value of the missing measurement (rounded off to the nearest 10 mm)?
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396.86 m
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396.79 m
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396.05 m
-
396.94 m
B
Correct answer
Explanation
For a closed traverse, the sum of latitudes and departures must be zero. By calculating the latitude (L = length * cos(azimuth)) and departure (D = length * sin(azimuth)) for each segment, one can solve for the missing length of PQ by setting the sum of all latitudes and departures to zero.
The following table gives data of consecutive coordinates in respect of a closed theodolite traverse PQRSP.
| |
|
|
|
|
| Station |
Northing, m |
Southing, m |
Easting, m |
Westing, m |
| P |
400.75 |
|
|
300.5 |
| Q |
100.25 |
|
199.25 |
|
| R |
|
199.0 |
399.75 |
|
| S |
|
300.0 |
|
200.5 |
The magnitude and direction of error of closure in whole circle bearing are respectively
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2.0 m and 45o
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2.0 m and 315o
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2.82 m and 315o
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3.42 m and 45o
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Geodetic surveying
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Plane surveying
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Preliminary surveying
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Topographical surveying
A
Correct answer
Explanation
Geodetic surveying accounts for the curvature of the earth, whereas plane surveying assumes the earth is a flat surface. This is necessary for large-scale surveys.