Physics
Current Electricity and Circuits
377 Questions
Current electricity and circuits questions cover resistors, EMF, internal resistance, and power calculations in series and parallel configurations. Solving these builds a strong understanding of electrical principles and circuit analysis. These physics problems are highly relevant for technical and science aptitude tests.
Resistor combinationsPower dissipationEMF and internal resistanceAC circuit analysisOperational amplifiers
Current Electricity and Circuits Questions
A
Correct answer
Explanation
RG-62 coaxial cable is characterized by its 93-ohm impedance, which distinguishes it from other common coaxial cable types. RG-58 uses 50 ohms (standard for Ethernet), RG-59 uses 75 ohms (commonly used for video/CATV), and RJ45 is an 8-pin connector (not a cable type). The 93-ohm impedance of RG-62 made it suitable for specific applications like IBM 3270 terminals and ARCnet networks.
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1/(R1+R2+R3+.......)
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R1R2R3....../R1+R2+R3+....
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R1+R2+R3+...........
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infinity
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1/(R1+R2+R3+..........)
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R1R2R3......../R1+R2+R3+......
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R1+R2+R3+..........
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Infinity
C
Correct answer
Explanation
In series circuits, resistances add directly (Rtotal = R1 + R2 + R3 + ...). Current must flow through each resistor sequentially, so the total resistance is the sum of all individual resistances.
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Kirchhoff's Current Law
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Ohm's Law
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Kirchhoff's Voltage Law
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Law of Superposition
B
Correct answer
Explanation
Ohm's Law states that voltage across a conductor equals current through it multiplied by resistance (V = I × R). Kirchhoff's laws deal with current junctions and voltage loops, while superposition is for analyzing circuits with multiple sources.
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Power(p) = Current squared(i?) x Resistance(R)
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Power(p) = Voltage squared(v?) / Resistance(R)
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Power(p) = Voltage(v) x Current(i)
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All of these
D
Correct answer
Explanation
All three formulas correctly calculate power dissipated by a resistor: P = I²R (from P = VI and V = IR), P = V²/R (substituting I = V/R), and P = VI (definition of power). They're mathematically equivalent through Ohm's Law.
A
Correct answer
Explanation
Ohm's Law states that the voltage (V) across a conductor is directly proportional to the current (I) flowing through it, with resistance (R) as the constant of proportionality, giving V = IR. The other options rearrange these variables incorrectly or don't represent Ohm's Law.
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R = ? A / L
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R = ? A L
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R = ? L / A
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R = ? / A L
C
Correct answer
Explanation
The resistance of a conductor is given by R = ρL/A, where ρ is resistivity, L is length, and A is cross-sectional area. Longer conductors have more resistance, thicker ones have less.
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I =V R
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P= I2 R
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V = I R
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R= V I
C
Correct answer
Explanation
Ohm's law states that voltage across a conductor is directly proportional to the current flowing through it. The correct relationship is V = IR, where V is voltage, I is current, and R is resistance. Option A incorrectly omits the division operation (should be I = V/R), option B is a power formula, and option D also omits division (should be R = V/I).
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V = I / R
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V = I . R
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V = I. I .R
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V= R. R
B
Correct answer
Explanation
Ohm's law states that the voltage across a conductor is directly proportional to the current flowing through it: V = IR, where V is voltage, I is current, and R is resistance. Option B correctly represents this relationship. Option A shows division instead of multiplication, and options C and D have nonsensical formulas.
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Req = R1 + R2
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Req = R1 + R2 + R3
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Req = R1 + R2 + R3 + . . . . . . + Rn
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Req = R1 - R2 - R3 - . . . . . . -Rn
C
Correct answer
Explanation
When resistors are connected in series, the equivalent (total) resistance is the sum of all individual resistances: R_eq = R₁ + R₂ + R₃ + ... + Rₙ. This is because the same current flows through each resistor, and the total voltage drop is the sum of individual voltage drops. Option C correctly represents the general formula for any number of resistors.
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L = ?n2L
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L = ?n2LA
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L = ?nhG
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L = ?n2LA/2
B
Correct answer
Explanation
The self-inductance of a solenoid is given by L = μ₀n²LA where μ₀ is permeability, n is turns per unit length, L is length, A is cross-sectional area. Option B shows the correct relationship.
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Ohm
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Amparas
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Ambrass
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Ampere
D
Correct answer
Explanation
The SI unit of electric current is the Ampere (A), named after André-Marie Ampère. Ohm is the unit of resistance. The options 'Amparas' and 'Ambrass' are misspellings or nonexistent units.
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4.0 Columbs
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5.0 Columbs
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6.0 Columbs
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7.0 Columbs
B
Correct answer
Explanation
Using the formula Energy = Voltage × Charge, we can calculate Charge = Energy / Voltage = 10J / 2V = 5 Coulombs. The relationship E = VQ is fundamental in electrical circuits.
C
Correct answer
Explanation
Ohm's Law states that the voltage (V) across a conductor is directly proportional to the current (I) flowing through it, with the constant of proportionality being the resistance (R). The correct formula is R = V/I, which can be rearranged to V = IR. Option A has the division reversed, option B multiplies V and I incorrectly, and option D has V squared which is incorrect.
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It equals the sum of the currents through each branch (Kirchoff's Current Law)
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It decreases as more parallel branches are added to the circuit
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It equals the average of each branch current
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It is the sum of the reciprocal of each individual voltage drop
A
Correct answer
Explanation
Kirchhoff's Current Law states that the total current entering a junction equals the total current leaving it. In parallel circuits, the total current equals the sum of individual branch currents, not the average or reciprocal sum.