Current Electricity and Circuits

According to resistor colour codeBlue = 6, gray = 8, Red = 2, black=0. So 6800 Ohms or 6.8k Ohms and tolerance is 10 % therefore 6800-680=6120 ohms.

According to resistor colour code brown= 1, red= 2, blue= 6, yellow= 4. Therefore value is: 120000 with +5%, we have to add max resistance, i.e.,  120000+5%=126000 ohms

In a series circuit, the current through each of the components is the same, and the voltage across the circuit is the sum of the voltages across each component

Conductance is the reciprocal of the resistance G=1/R, where R= resistance 1/8=0.125=125ms.

Current (ampere, A) = charge (coulomb, C) / time (second, s) i = Q / t i = (8/10)/4 i = 2/10 i = 0.2 A.

The three-terminal variable resistor is also known as the potentiometer.

If one of the parallel resistors shorted out, then the voltage across all of them would be zero (short) volts. Since,  the voltage across the other resistors is zero, the current would also be zero.

According to resistor color code RED is 2 orange 3 and third orange 10 to the power of that value so 10000 so R= 23000 I= V/R= 40/23000= 1.74 mA.

According to ohms law, V= IR. Where V= IRV = 34*2.V = 68 Volts.

I= 750mA, I= 750*10^3A, V= 150V,R= V/I; R= 150/(750*10^3); R= 200 ohm.

V = IR. R = V/I R = 4.5/30 *10^-3  R = 150 Ohm.

TOTAL POWER P = v^2*(R1+R2/R1*R2)  = V^2/R2+V^2/R1  = P1+P2  = 16W

When the bulb glows: V = I R ---- Ohm's law R = V/I = 2/.2 =10 Ω

Current is the ratio of charge to time. The quantity of charge passing through a cross section in 2 seconds is 10 C. The ratio of charge to time isI = Q / t = ( 10 C) / ( 2 s) = 5 C/s = 5 Ampere

If R is the equivalent resistance of the circuit, then R = V/I = 12/ 0.5 = 24 Ω But, R = R1 + R2, ∴ 24 = 22 + R2, ∴ R2 = 2 Ω