Chemistry

Chemical Bonding and Molecular Structure

1,420 Questions

This section tests your knowledge of chemical bonding, molecular structure, and hybridization. It covers ionic and covalent bonds, octet rule exceptions, and molecular geometry. These chemistry questions are common in various competitive entrance examinations.

Ionic and covalent bondsHybridisation of elementsOctet rule exceptionsMolecular geometryIntermolecular forces

Chemical Bonding and Molecular Structure Questions

Multiple choice
  1. 1

  2. 2

  3. 0

  4. 4

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Oxygen has six valence electrons and requires two more to complete its outer octet. Therefore, it typically forms two covalent bonds to achieve stability.

Multiple choice
  1. is an intermolecular force

  2. is a van der Waals force

  3. is an Ionic Bond

  4. is a Hydrogen Bond

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

A hydrogen bond is an attractive intermolecular force that occurs between a partially positive hydrogen atom (covalently bonded to a highly electronegative atom) and a partially negative electronegative atom (like oxygen or nitrogen) on a neighboring molecule.

Multiple choice
  1. PA

  2. P

  3. H2O

  4. K

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The chemical symbol for potassium is K, which comes from its Neo-Latin name "kalium." P is the symbol for phosphorus, PA is not a standard single-element symbol (though Pa is protactinium), and H2O is the chemical formula for water.

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts

Which of the following diazonium salt is relatively stable at $0-{ 5^0 }^{ }C$?

  1. ${ CH } _{ 3 }-N\equiv N{ \} }^{ \oplus }C{ l }^{ - }$
  2. ${ \left( { CH } _{ 3 } \right) } _{ 2 }CH-N\equiv N{ \} }^{ \oplus }{ Cl }^{ - }$
  3. ${ C } _{ 6 }{ H } _{ 5 }-N\equiv N{ \} }^{ \oplus }{ Cl }^{ - }$
  4. ${ \left( { CH } _{ 3 } \right) } _{ 3 }C-N\equiv N{ \} }^{ \oplus }{ Cl }^{ - }$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The $+I$ effect which stabilizes the ${ N }^{ + }$ion is in the following order ${ C } _{ 6 }{ H } _{ 5 }-<{ CH } _{ 3 }-<{ \left( { CH } _{ 3 } \right)  } _{ 2 }-<{ \left( { CH } _{ 3 } \right)  } _{ 3 }$

$\therefore $ The ${ \left{ { \left( { CH } _{ 3 } \right)  } _{ 3 }C-N\equiv N \right}  }^{ + }{ Cl }^{ - }$ is most stable

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts

Which of the following amines form unstable diazonium salt?

  1. ${ C } _{ 6 }{ H } _{ 5 }{ NH } _{ 2 }$
  2. $\left( { C } _{ 2 }{ H } _{ 5 } \right) _{ 2 }NH$
  3. $\left( { C } _{ 2 }{ H } _{ 5 } \right) _{ 3 }N$
  4. ${ CH } _{ 3 }{ NHC } _{ 2 }{ H } _{ 5 }$
Reveal answer Fill a bubble to check yourself
B,C,D Correct answer
Explanation

Only primary aromatic amines form stable arene diazonium salts.
The reaction is as follows:

$C _{6}H _{5}NH _{2} + NaNO _{2} + HCl (0-5^{\circ}C) \rightarrow PhN _{2}^{+}Cl^{-}$

Remain forms the unstable diazonium salt.
So, the correct options are $B$, $C$, $D$

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts

Which of the following amines will form stable diazonium salt at 273-283 K? 

  1. $\displaystyle { C } _{ 2 }{ H } _{ 5 }{ NH } _{ 2 }$
  2. $\displaystyle { C } _{ 6 }{ H } _{ 5 }{ NH } _{ 2 }$
  3. $\displaystyle { C } _{ 6 }{ H } _{ 5 }{ CH } _{ 2 }{ NH } _{ 2 }$
  4. $\displaystyle { C } _{ 6 }{ H } _{ 5 }{ N\left( { CH } _{ 3 } \right) } _{ 2 }$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Aniline (C6H5NH2) is a primary aromatic amine, which reacts with nitrous acid at 273-278 K to form benzenediazonium chloride, which is relatively stable at this temperature due to resonance. Aliphatic amines like C2H5NH2 and C6H5CH2NH2 form highly unstable diazonium salts that decompose immediately, while tertiary aromatic amines like C6H5N(CH3)2 undergo electrophilic aromatic substitution (nitrosation) instead of diazotization.

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts

Which of the following diazonium salt is relatively stable of $0-5^\circ C$- :

  1. $CH _{3}CH _2N\equiv N\left. \right \} ^\oplus Cl^{-} $
  2. $CH _{3}-C(CH _{3}) _{2}-N\equiv N\left. \right \} ^\oplus Cl^{-} $
  3. $CH _{3}-N\equiv N\left. \right \} ^\oplus Cl^{-} $
  4. $(CH _{3}) _{3}C-N\equiv N\left. \right \} ^\oplus Cl^{-} $
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The diazonium salt  $CH _{3}-N\equiv N\left.  \right } ^\oplus Cl^{-}$ obtained by treatment of methylamine with nitrous acid is relatively stable at $0-5^\circ C$.

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts

Which of the following diazonium salt is relatively stable at $\displaystyle 0-5^{\circ}$C?

  1. $\displaystyle CH _{3}-N\equiv N \left. \right \}^{\oplus }Cl^{-}$
  2. $\displaystyle CH _{3}C\left ( CH _{3} \right )-N\equiv N \left. \right \}^{\oplus }Cl^{-}$
  3. $\displaystyle C _{6}H _{5}-N\equiv N \left. \right \}^{\oplus }Cl^{-}$
  4. $\displaystyle \left ( CH _{3} \right ) _{3}C-N\equiv N \left. \right \}^{\oplus }Cl^{-}$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Diazonium salts obtained from aliphatic primary amines are unstable. Those obtained from aromatic primary amines are relatively stable.
Benzene diazonium chloride $(\displaystyle C _{6}H _{5}-N\equiv N \left.  \right }^{\oplus }Cl^{-})$ is obtained from aromatic primary amine. Hence, it is relatively stable.

Multiple choice chemistry amines introduction to diazonium salts structure, preparation and physical properties of diazonium salts diazonium salts

Arrange the following resonating structure according to their contribution towards resonance hybrid?
(a) $CH _2=\overset {\oplus}{N}=\overset {\ominus}{N}$ (b) $\overset {\ominus}{C}H _2-N=\overset {\oplus}{N}:$ (c) $\overset {\oplus}{C}H _2-\underset {. .}{N}=\overset {\ominus}{N}$ (d) $\overset {\ominus}{C}H _2-\overset {\oplus}{N}\equiv \overset {. .}{N}$

  1. a > d > c > b

  2. b > a > c > d

  3. a > c > b > d

  4. d > a > b > c

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
The correct order of the contribution of resonating structure towards resonance hybrid is
$\displaystyle a (CH _2=\overset {\oplus}{N}=\overset {\ominus}{N}) > d (\overset {\ominus}{C}H _2-\overset {\oplus}{N}\equiv \overset {. .}{N}) > c (
\overset {\oplus}{C}H _2-\underset {. .}{N}=\overset {\ominus}{N}
) > b (\overset {\ominus}{C}H _2-N=\overset {\oplus}{N}:)$
a and d have higher contribution as they have less charge separation.
b and c have lower contribution as they have more charge separation.