Quantitative Aptitude

Problems on Ages

1,744 Questions
All Translate multiples, fractions, and percentages 518 Use two ratios from different dates 500 Convert an age ratio into actual ages 258 Handle averages and changing groups 167 Generational age chains 111 Recognize equal age gaps 101 Product of ages 68 Ages in arithmetic progression 11 Division of lifespan 9

Problems on Ages Questions

Multiple choice

Meena's age is four times her son's present age and four seventh of her father's age. The average of the present ages of all of them is 32 years. What is the difference between the Meena's son's present age and Meena's father's present age?

  1. 44 years

  2. 48 years

  3. 46 years

  4. 42 years
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let son's age = x. Then Meena = 4x, and father = (7/4)(4x) = 7x. Average = (x + 4x + 7x)/3 = 4x = 32, so x = 8. Father-son difference = 7x - x = 48 years. Answer B is correct.

Multiple choice

A couple has one son and one daughter. Father's age is four times of his son and daughter age is one third of her mother's age. If wife is 6 year younger than husband and sister is 3 year older than her brother then find the present age of mother?

  1. 54

  2. 52

  3. 56

  4. 50

  5. 60
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let son's age be x. Father is 4x. Daughter is x+3. Mother is 3 times daughter, so 3(x+3). Wife is 6 years younger than husband, so 4x - 6 = 3x + 9. Solving gives x = 15, so mother is 3(18) = 54 years.

Multiple choice

The age of Jaya 10 years ago is equal to Ritu's present age. The sum of Jaya's age 8 years hence from today and Ritu's age 12 years ago is 90 years. Then what was the age of Neha 13 years ago from now if Neha is 9 years younger than Ritu?

  1. 20 year

  2. 21 year

  3. 22 year

  4. 23 year

  5. 24 year
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let Jaya's present age = J, Ritu's present age = R. From statement 1: J - 10 = R, so J = R + 10. From statement 2: (J + 8) + (R - 12) = 90, so J + R - 4 = 90, giving J + R = 94. Substituting J = R + 10: (R + 10) + R = 94, so 2R = 84, giving R = 42. Then J = 52. Neha is 9 years younger than Ritu, so Neha's present age = 42 - 9 = 33. Neha's age 13 years ago = 33 - 13 = 20. Option A is correct.

Multiple choice

The ratio between the ages of A and B is 3: 5 and the sum of their ages is 56 years. The ratio between their ages 7 years ago was- A और B की आयु का अनुपात 3: 5 है और उनकी आयु का योग 56 वर्ष है। तदनुसार,7 वर्ष पहले उनकी आयु का अनुपात क्या था?

  1. 1 : 2

  2. 2 : 3

  3. 3 : 4

  4. 3 : 5
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Given ratio A:B = 3:5 and sum = 56 years. So A = 3x = 21 years, B = 5x = 35 years (where 8x = 56, x = 7). Seven years ago: A was 14, B was 28. Ratio = 14:28 = 1:2. Option B (2:3), C (3:4), and D (3:5) are incorrect - these don't match the calculated ages 7 years ago.

Multiple choice

The ages of Sonal and Nitya are in the ratio 9 : 5 respectively. After 8 years the ratio of their ages will be 13 : 9. What is the difference in years between their ages? सोनल और नित्य की आयु में अनुपात 9 : 5 है | 8 वर्षों बाद उनकी आयु में अनुपात 13 : 9 हो जाता है | उनकी आयु में अनुपात वर्षों में है

  1. 6 years/वर्ष

  2. 8 years/वर्ष

  3. 12 years/वर्ष

  4. 14 years/वर्ष
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let Sonal's age = 9x, Nitya's age = 5x. After 8 years: (9x+8)/(5x+8) = 13/9. Cross-multiplying: 9(9x+8) = 13(5x+8), 81x + 72 = 65x + 104, 16x = 32, x = 2. Current ages: Sonal = 18, Nitya = 10. Difference = 8 years. The age difference remains constant over time, which provides a useful check: 18 - 10 = 8 years apart.

Multiple choice

A is 4 years younger than B. B is 12 years younger than C. 4 years hence the ratio between C and A is 9:5, Find the age of B?

  1. 24

  2. 16

  3. 20

  4. 28

  5. 32
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let C's current age be x. Then B's age = x - 12 and A's age = x - 16. After 4 years: C's age = x + 4, A's age = x - 12. The ratio (x+4)/(x-12) = 9/5 gives x = 32. So B = 32 - 12 = 20 years. Option A (24) would mean C = 36, making the ratio 40:20 = 2:1, not 9:5. Option D (28) would mean C = 40, giving ratio 44:24 = 11:6, which is incorrect.

Multiple choice

Present age of Naimish is equal to Deepak’s age 8 years ago. Four years hence, the respective ratio between Naimish’s age and Deepak’s age will be 4 : 5 at that time. What is Naimish’s present age?

  1. 28

  2. 30

  3. 26

  4. 32

  5. 24
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let Naimish's present age be N and Deepak's present age be D. Given N = D - 8. Four years hence: (N + 4)/(D + 4) = 4/5. Cross-multiply: 5N + 20 = 4D + 16. Substitute N = D - 8: 5(D - 8) + 20 = 4D + 16. This gives 5D - 40 + 20 = 4D + 16, so D = 36. Therefore N = 36 - 8 = 28. Option A is correct.

Multiple choice

A father tells his son, “ I was three times of your present age when you were born. “if the father’s present age is 48 years how old was the boy 4 years ago? एक पिता अपने पुत्र से कहता है ‘‘जब तुम पैदा हुए थे तब मैं तुम्हारी वर्तमान आयु का तीन गुना था।‘‘ यदि पिता की वर्तमान आयु 48 वर्ष है तो 4 वर्ष पहले पुत्र की आयु कितनी थी ?

  1. 12

  2. 10

  3. 7

  4. 8
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let son's current age = x. When son was born (age 0), father was 3x years old. Father's current age (48) = 3x + x = 4x. So x = 12. Son's age 4 years ago = 12 - 4 = 8 years.

Multiple choice

A fathers age is 5 times more than his son. this sons age is 6 years so after how many years he would be four times his son?/ एक पिता अपने पुत्र से 5 गुना बड़ा हैं उसका पुत्र 6 का है। कितने वर्ष बाद वह अपने से 4 गुना बड़ा होगा?

  1. 2

  2. 3

  3. 4

  4. 5
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The son's current age is 6 years. Father is 5 times more than son, so father = 6 + 5*6 = 36 years. After x years, father will be 4 times the son. (36+x) = 4*(6+x). Solving: 36+x = 24+4x, so 12 = 3x, and x = 4. However, the question states father is 5 times MORE than son (5 times more = 6 times total), so father = 36. After 2 years: father = 38, son = 8. 38/8 = 4.75, not 4. Let me reconsider: if father is 5 times MORE (meaning 6 times total), then father = 6*6 = 36. After x years: (36+x) = 4*(6+x). 36+x = 24+4x. 12 = 3x. x = 4. But option A is 2, not 4. Let me try another interpretation: if 5 times more means 5+6=11 total, then father = 11*6 = 66. After x years: (66+x) = 4*(6+x). 66+x = 24+4x. 42 = 3x. x = 14. That's not an option either. The correct interpretation is likely that father is 5 times the son's age (not 5 times MORE), so father = 5*6 = 30. After x years: (30+x) = 4*(6+x). 30+x = 24+4x. 6 = 3x. x = 2. This matches option A.

Multiple choice

The age of Ram is 4 times of his son. the age of Ram was 9 times of his son's age five years ago. Find their present ages. राम की आयु उसके बेटे की आयु का चार गुना है, राम की आयु पांच वर्ष पहले अपने बेटे की आयु का 9 गुना थी | उनकी वर्तमान आयु ज्ञात कीजिये |

  1. 32, 5 years/वर्ष

  2. 32, 10 years/वर्ष

  3. 32, 8 years/वर्ष

  4. 40, 8 years/वर्ष
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let Ram's present age = R, son's present age = S. Given: R = 4S. Five years ago: R - 5 = 9(S - 5). Substituting: 4S - 5 = 9S - 45. Solving: 5S = 40, so S = 8 years and R = 32 years.

Multiple choice

Rakesh got married 8 years ago. His present age is sixth-fifth times at the times of his marriage age. Rakesh's sister was 10 year younger to him at the time of his marriage. The age of Rakesh's sister. राकेश का विवाह 8 वर्ष पूर्व हुआ था। उसकी वर्तमान आयु उसके विवाह के समय की आयु का षट्-पंचमाश गुना है। राकेश की बहन उसके विवाह के समय उससे 10 वर्ष छोटी थी। राकेश की बहन की आयु है-

  1. 38 year/वर्ष

  2. 36 year/वर्ष

  3. 32 year/वर्ष

  4. 34 year/वर्ष
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let Rakesh's age at marriage be x. Present age = (6/5)x = x + 8, giving x = 40. So present age is 48. Sister at marriage was 40 - 10 = 30 years old. Sister's present age = 30 + 8 = 38 years.

Multiple choice

Ram is 20 years younger than Shyam. After 5 years Ram will be two-third times of Shyam, then find the present age of Ram. राम, श्याम से 20 वर्ष छोटा है। पॉच वर्ष बाद राम, श्याम का दो तिहाई गुना होगा तो राम की वर्तमान आयु ज्ञात कीजिए।

  1. 35 years /वर्ष

  2. 40 years /वर्ष

  3. 45 years /वर्ष

  4. 60 years /वर्ष
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let Ram's current age = R, Shyam's current age = S. Given R = S - 20. After 5 years: R + 5 = (2/3)(S + 5). Substitute R = S - 20: S - 20 + 5 = (2/3)(S + 5), so S - 15 = (2/3)(S + 5). Multiply by 3: 3S - 45 = 2S + 10, giving S = 55. Then R = 55 - 20 = 35. Ram's present age is 35 years. Option A is correct.

Multiple choice

The average age of father and his son is 22 years. The ratio of their ages is 10 : 1 respectively. What is the age of the son? पिता और उनके पुत्र की औसत आयु 22 वर्ष है। उनकी आयु का अनुपात क्रमशः 10: 1 है। पुत्र की उम्र क्या है?

  1. 8

  2. 40

  3. 14

  4. 4
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Average age of father and son is 22 years, so their total age is 44 years. Given the ratio 10:1, let son's age be x, then father's age is 10x. So x + 10x = 44, giving 11x = 44, so x = 4. Therefore son's age is 4 years and father's age is 40 years. Option D (4) is correct.

Multiple choice

The average of the students in a class is 30 years. If two students whose age was 21years and 23 years are absent from the class, the average of those present goes up by 0.5. How many students were there in the class originally? एक कक्षा में छात्रों की औसत 30 साल है। यदि दो छात्रों की उम्र 21 वर्ष और 23 साल कक्षा से अनुपस्थित है, तो उन उपस्थित छात्रों का औसत 0.5 ऊपर चला जाता है। मूल रूप से कक्षा में कितने छात्र थे?

  1. 29

  2. 34

  3. 24

  4. 31
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let n be original students. Total age = 30n. After removing two students (ages 21, 23), total = 30n - 44 and students = n - 2. New average is 30.5, so (30n-44)/(n-2) = 30.5. Solving: 30n-44 = 30.5n - 61, so 17 = 0.5n, giving n = 34.