Multiple choice

A couple has one son and one daughter. Father's age is four times of his son and daughter age is one third of her mother's age. If wife is 6 year younger than husband and sister is 3 year older than her brother then find the present age of mother?

  1. 54

  2. 52

  3. 56

  4. 50

  5. 60
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A Correct answer
Explanation

Let son's age be x. Father is 4x. Daughter is x+3. Mother is 3 times daughter, so 3(x+3). Wife is 6 years younger than husband, so 4x - 6 = 3x + 9. Solving gives x = 15, so mother is 3(18) = 54 years.

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