Quantitative Aptitude

Problems on Ages

1,744 Questions
All Translate multiples, fractions, and percentages 518 Use two ratios from different dates 500 Convert an age ratio into actual ages 258 Handle averages and changing groups 167 Generational age chains 111 Recognize equal age gaps 101 Product of ages 68 Ages in arithmetic progression 11 Division of lifespan 9

Problems on Ages Questions

Multiple choice

Present ages of Richa and her husband are in ratio 3 : 4. Five years from now, ages of her husband and her son will be in ratio 3 : 1. If the present age of Richa is 21 years, then what will be her son's present age (in years)?

  1. 16

  2. 11

  3. 6

  4. 5
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Richa's age is 21. Given the ratio of Richa to her husband is 3:4, her husband's age is (21/3)*4 = 28. In 5 years, the husband will be 33. The ratio of husband to son is 3:1, so the son's age in 5 years will be 33/3 = 11. Therefore, the son's present age is 11 - 5 = 6.

Multiple choice

Present ages of Ram and his father are in the ratio 2 : 3. After 5 years, ratio of ages of Ram's father and his mother will be 13 : 12. If the present age of his mother is 55 years, then what will be the age of Ram (in years) 7 years from now?

  1. 43

  2. 47

  3. 42

  4. 45
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The coefficient of variation (CV) is (Standard Deviation / Mean) * 100. Mean = Assumed Mean + (Sum of deviations / N) = 4 + (-11/100) = 3.89. Variance = (Sum of squares of deviations / N) - (Sum of deviations / N)^2 = (257/100) - (-11/100)^2 = 2.57 - 0.0121 = 2.5579. SD = sqrt(2.5579) = 1.599. CV = (1.599 / 3.89) * 100 = 41.11%.

Multiple choice

Manu is 3 years younger than Sumit, while Aseem is 2 years younger than Manu. The ratio of age of Sumit 4 years hence to the age of Manu 3 years ago is 5 : 3. What was the age of Aseem 2 years ago?

  1. 8 years

  2. 10 years

  3. 12 years

  4. 14 years

  5. 16 years
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let M = Manu's age, S = Sumit's age, A = Aseem's age. M = S - 3, A = M - 2. Given (S + 4) / (M - 3) = 5/3. Substituting S = M + 3 gives (M + 7) / (M - 3) = 5/3, so 3M + 21 = 5M - 15, 2M = 36, M = 18. Then A = 16. Aseem's age 2 years ago was 16 - 2 = 14.

Multiple choice

Average age of Mohak and Davinder 3 years ago was 32. After 7 years, age of Mohak will be 46 years and Davinder will be 3 years older than another friend Jatin. What will be the sum of present ages of Mohak and Jatin?

  1. 65 years

  2. 67 years

  3. 69 years

  4. 73 years

  5. 75 years
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Mohak and Davinder's average age 3 years ago was 32, so their sum was 64. Their current sum is 64 + 3 + 3 = 70. In 7 years, Mohak will be 46, so his current age is 39. Thus, Davinder's current age is 70 - 39 = 31. Davinder is 3 years older than Jatin, so Jatin is 31 - 3 = 28. The sum of Mohak and Jatin's current ages is 39 + 28 = 67.

Multiple choice

Virat and Rohit are brothers. Four years ago, the ratio of the ages of Virat and Rohit was 10 : 18. Eight years hence, the ratio will be 2 : 3, respectively. Find the present age of Rohit.

  1. 50 years

  2. 36 years

  3. 40 years

  4. 20 years

  5. 25 years
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let ages 4 years ago be 10x and 18x. Present ages: 10x+4, 18x+4. (10x+4+8)/(18x+4+8) = 2/3. (10x+12)/(18x+12) = 2/3. 30x+36 = 36x+24. 6x = 12, x = 2. Rohit's present age = 18(2)+4 = 40.

Multiple choice

One year ago, Ram's age was four times that of Rohan's age. Six years hence, Ram's age will be 9 years more than Rohan's age. Find the ratio of present ages of Ram and Rohan.

  1. 13 : 3

  2. 13 : 4

  3. 13 : 5

  4. 13 : 6

  5. 13 : 7
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let Ram's age be R and Rohan's be H. (R-1) = 4(H-1) => R-1 = 4H-4 => R = 4H-3. (R+6) = (H+6) + 9 => R+6 = H+15 => R = H+9. Equating: 4H-3 = H+9 => 3H = 12 => H=4. Then R = 4+9 = 13. Ratio R:H = 13:4.

Multiple choice

The average age of three persons - A, B and C - is 44 years. The ratio of the ages of A and C is 3 : 4 and the sum of the ages of A and C is 98 years. Find the sum of the ages of B and C.

  1. 80 years

  2. 85 years

  3. 90 years

  4. 95 years

  5. 100 years
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Average of A, B, C is 44, so A+B+C = 132. Given A+C = 98, then B = 132 - 98 = 34. Since A:C = 3:4 and A+C = 98, 7 parts = 98, so 1 part = 14. A = 42, C = 56. B+C = 34 + 56 = 90.

Multiple choice

The present age of son is 4 times the difference between the present ages of father and mother. If the age of father is 3 times the age of son, and mother is 3 years younger than father, then what is the present age of son?

  1. 4 years

  2. 8 years

  3. 12 years

  4. 16 years

  5. None of the above
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let S, F, M be ages. S = 4(F - M). F = 3S. M = F - 3 = 3S - 3. Substitute M and F into the first equation: S = 4(3S - (3S - 3)) = 4(3S - 3S + 3) = 4(3) = 12.