Multiple choice

Manu is 3 years younger than Sumit, while Aseem is 2 years younger than Manu. The ratio of age of Sumit 4 years hence to the age of Manu 3 years ago is 5 : 3. What was the age of Aseem 2 years ago?

  1. 8 years

  2. 10 years

  3. 12 years

  4. 14 years

  5. 16 years
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let M = Manu's age, S = Sumit's age, A = Aseem's age. M = S - 3, A = M - 2. Given (S + 4) / (M - 3) = 5/3. Substituting S = M + 3 gives (M + 7) / (M - 3) = 5/3, so 3M + 21 = 5M - 15, 2M = 36, M = 18. Then A = 16. Aseem's age 2 years ago was 16 - 2 = 14.

AI explanation

Let Sumit's present age be S. Manu is S minus 3 and Aseem is S minus 5. The ratio of Sumit's age in 4 years (S plus 4) to Manu's age 3 years ago (S minus 6) is 5 to 3, giving the equation 3S plus 12 equals 5S minus 30. Solving this shows S equals 21. Aseem's present age is 16, so his age 2 years ago was 14.

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