Quantitative Aptitude
Problems on Ages
1,744 Questions
Problems on Ages Questions
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13 years
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14 years
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15 years
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16 years
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17 years
C
Correct answer
Explanation
Let J = 3M. After 5 years, J+5 = 2(M+5). 3M+5 = 2M+10 -> M = 5. J = 3(5) = 15.
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25 years
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30 years
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35 years
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40 years
A
Correct answer
Explanation
Let f be father's age, s be son's age. f + 2s = 70 and 2f + s = 95. Adding equations: 3f + 3s = 165, so f + s = 55. Subtracting equations: f - s = 25.
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38 years
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39 years
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40 years
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41 years
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42 years
A
Correct answer
Explanation
Present sum of father and son = 29 * 2 = 58. Five years from now, sum of father, mother, and son = 37 * 3 = 111. Their present sum = 111 - (3 * 5) = 111 - 15 = 96. Mother's age = 96 - 58 = 38.
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45 years
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50 years
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40 years
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Cannot be determined
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None of these
B
Correct answer
Explanation
Let D be the daughter's age, R be Raman's age, and M be his mother's age. R = 3D and R = (9/13)M. Thus, M = (13/9)R = (13/9)(3D) = (13/3)D. The sum D + R + M = 125, so D + 3D + (13/3)D = 125. Multiplying by 3 gives 3D + 9D + 13D = 375, so 25D = 375, D = 15. Then R = 45 and M = 65. The difference M - D = 65 - 15 = 50.
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5 : 3
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13 : 16
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17 : 7
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18 : 3
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20 : 7
A
Correct answer
Explanation
Let ages be F and S. F+S = 100. Five years ago, (F-5)/(S-5) = 2/1, so F-5 = 2S-10, F = 2S-5. Substitute: 2S-5+S = 100, 3S = 105, S = 35, F = 65. After 10 years, ages are 75 and 45. Ratio 75:45 = 5:3.
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35 years
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30 years
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25 years
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8 years
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5 years
D
Correct answer
Explanation
Let Hilary's age be H, Patricia's age be H + 5. Three years ago, ages were H - 3 and H + 2. (H + 2)^2 - (H - 3)^2 = 25. (H^2 + 4H + 4) - (H^2 - 6H + 9) = 25. 10H - 5 = 25. 10H = 30, H = 3. Hilary's age 5 years from now = 3 + 5 = 8.
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2x + 3y = 2
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x = 2y + 4
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x = y + 2
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x + 4y = 2
C
Correct answer
Explanation
Jacob's age (x) is 2 years more than David's age (y). This is expressed as x = y + 2.
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40 years
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28 years
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32 years
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30 years
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33 years
C
Correct answer
Explanation
Sum of ages after 10 years = 104 + 30 = 134. Ratio 27:21:19 sums to 67. Each part = 134/67 = 2. B's age after 10 years = 21 * 2 = 42. Present age = 42 - 10 = 32.
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35 years
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36 years
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37 years
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38 years
B
Correct answer
Explanation
The sum of the ages is 52. If the son is 16, the mother's age is 52 - 16 = 36.
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28 years
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32 years
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26 years
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30 years
D
Correct answer
Explanation
Let Meena's age be 16x and Fiona's be 13x. Four years ago: (16x-4)/(13x-4) = 14/11. 11(16x-4) = 14(13x-4) => 176x - 44 = 182x - 56 => 6x = 12 => x = 2. Fiona's present age = 13 * 2 = 26. Four years from now, she will be 26 + 4 = 30.
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63 years
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45 years
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40 years
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54 years
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55 years
B
Correct answer
Explanation
Let ages be 9x and 4x. After 5 years: (9x+5)/(4x+5) = 2/1. 9x+5 = 8x+10, so x = 5. Father's age = 9*5 = 45.
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36 years
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20 years
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24 years
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21 years
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None of these
B
Correct answer
Explanation
Four years ago, the sum of ages of 4 friends was 21 * 4 = 84. At present, their sum is 84 + (4 * 4) = 100. With the new friend, the sum of 5 friends is 24 * 5 = 120. The new friend's age is 120 - 100 = 20.
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4 years
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8 years
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10 years
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12 years
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None of these
A
Correct answer
Explanation
Let ages be 5x and 6x. (5x+8)/(6x+8) = 7/8. 40x + 64 = 42x + 56. 2x = 8, so x = 4. The difference is 6x - 5x = x = 4 years.
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14 years and 15 years
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19 years and 20 years
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15 years and 16 years
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17 years and 16 years
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None of these
C
Correct answer
Explanation
Let ages 5 years ago be 10x and 11x. Present ages are 10x+5 and 11x+5. After 7 years, ages are 10x+12 and 11x+12. Ratio (10x+12)/(11x+12) = 22/23. Solving gives 230x + 276 = 242x + 264, so 12x = 12, x = 1. Present ages are 15 and 16.
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25 years
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28 years
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35 years
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30 years