To solve this question, the user needs to understand the concept of object comparison in Java and how it differs from primitive type comparison.
In Java, objects are compared using the ==
operator. When comparing two objects using ==
, Java checks if the two objects refer to the same memory location. If they do, the ==
operator returns true; otherwise, it returns false.
Now let's go through each option and explain why it is right or wrong:
A. Compiler error: This option is incorrect. There is no compilation error in the given code. The code will compile successfully.
B. Runtime Exception: This option is incorrect. There is no runtime exception in the given code. The code will run without throwing any exceptions.
C. True: This option is incorrect. Although the values of a
and b
are both 2, the variables a
and b
are objects of the Integer
class. When comparing objects using ==
, Java checks if they refer to the same memory location, not their values. In this case, a
and b
are different objects, even though their values are the same. Therefore, a == b
will return false.
D. False: This option is correct. As explained earlier, a
and b
are different objects, even though their values are the same. Therefore, a == b
will return false.
The answer is: D. False