A series expansion for the function sin$\theta$ is
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1 - $\frac{\theta^2}{2!} + \frac{\theta^4}{4!}$
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$\frac{\theta^3}{3!} + \frac{\theta^5}{5!}$
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1 + $\theta$+ $\frac{\theta^2}{2!} + \frac{\theta^3}{3!}$
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$\theta$ + $\frac{\theta^3}{3!} + \frac{\theta^5}{5!}$
B
Correct answer
Explanation
$\text{We know the series expansion of} \\
sin \theta = \theta - \frac{\theta^3}{\lfloor{3}} + \frac{\theta^3}{\lfloor{5}} - \frac{\theta^7}{\lfloor{7}}+ ......$