Multiple choice

The Taylor series expansion of $\frac{sin x}{x - \pi}$ at x = $\pi$ is given by

  1. 1 + $\frac{(x - \pi)^2}{3!} + ...$
  2. - 1 - $\frac{(x - \pi)^2}{3!} + ...$
  3. 1 - $\frac{(x - \pi)^2}{3!} + ...$
  4. - 1 + $\frac{(x - \pi)^2}{3!} + ...$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Keep practicing — related questions