Choices 1, 2, 4 and 5 can be even or odd depending on the value chosen for n.
Now, n3 - n = n(n2 -1) = n(n +1)(n - 1) = (n - 1)(n)(n + 1).
This is the product of 3 consecutive integers at least one of which will be even.
Hence, the product will always be even.
Hence, choice (3) wil always be even.