Since we have to test all the choices, Let us consider one odd value (1) for k. Then (1) = 1, (2) = 0 , (3) = 0, (4) = 4 and (5) = 7. Now let us consider one even value (2) for k. Then (1) = 4, (2) = 2, (3) = 1, (4) = 7 and (5) = 11.In both cases Choice (2) is even, is the answer.