To answer this question, let's break down each option:
Option A) After object B is notified, or after two seconds
Option B) After the lock on B is released, or after two seconds
Option C) Two seconds after object B is notified
Option D) Two seconds after lock B is released
The correct answer is A) After object B is notified, or after two seconds.
Explanation:
When the wait(2000) method is called on an object, it causes the current thread to release the lock on that object and enter a waiting state. The thread will remain in the waiting state until one of two conditions is met:
- The object is notified by another thread using the
notify() or notifyAll() method.
- The specified time (2000 milliseconds in this case) has elapsed.
In this scenario, thread A will become a candidate to get another turn at the CPU either when object B is notified or after two seconds, whichever comes first. So option A is correct.
Option B is incorrect because the thread does not need to wait for the lock on object B to be released. The wait(2000) method already releases the lock.
Option C is incorrect because the thread does not wait for two seconds after object B is notified. It can become a candidate to get another turn at the CPU immediately after being notified.
Option D is incorrect because the thread does not wait for two seconds after releasing the lock on object B. It can become a candidate to get another turn at the CPU immediately after releasing the lock.
Therefore, the correct answer is A) After object B is notified, or after two seconds.