What is the output of following piece of code ?
int x = 2;
switch (x) {
case 1:System.out.println("1?);
case 2:
case 3:System.out.println("3?);
case 4:
case 5:System.out.println("5?);
}
-
No output
-
3 and 5
-
1, 3 and 5
-
3
To solve this question, the user needs to understand the concept of switch case statements in Java. The switch statement tests the value of a variable and compares it with multiple cases. If a case matches the value of the variable, then the code inside that case is executed. If no matching cases are found, then the default case is executed.
In the given code, the variable x is initialized to 2. The switch statement checks the value of x, and since it matches the case 2, the code inside that case is executed. Since there are no break statements, the control falls through to the next case, which is 3. Thus, the output will be "3?".
The case for 1 and 5 are not executed because the value of x is not equal to 1 or 5.
Option A is incorrect because there is output from the code. Option B is incorrect because the output is not just 3 and 5. Option C is incorrect because there is no output for 1.
Therefore, the answer is:
The Answer is: D. 3
In Java, a switch without break statements falls through to subsequent cases. With x=2, execution jumps to case 2:, which has no statement and falls into case 3:, printing "3". Since case 3 also has no break, execution continues into case 4: (no statement) and then case 5:, printing "5". So two lines are printed in sequence: "3" then "5" — i.e. output is "3 and 5", not just "3" alone (that would only be true if a break existed after case 3). Answer id 833 ("3 and 5") is the single correct description of the program's output; answer id 835 ("3" alone) is an incomplete/incorrect description of the same run and should not also be marked correct — it omits the guaranteed fallthrough print of "5".