Multiple choice

Which of the following functions would have only odd powers of x in its Taylor series expansion about the point x = 0?

  1. sin x3

  2. sin x2

  3. cos x3

  4. cos x2
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

$sin x = x + \frac{x^3}{3!}+\frac{x^5}{5!}+ ... \\ cos x = 1 + \frac{x^2}{2!}+\frac{x^4}{4!}+ ... \\ \text{Thus only $(x^3)$ will have odd power of x.}$

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