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Multiple choice

Let $a,\ b$ and $c$ be three distinct real roots of the cubic $x^{3}+2x^{2}-4x-4=0$. If the equation $x^{3}+qx^{2}+rx+s=0$ has roots $\dfrac{1}{a},\ \dfrac{1}{b}$ and $\dfrac{1}{c}$ , then the value of $(q+r+s)$ is equal to

  1. $\dfrac{-3}{4}$
  2. $\dfrac{1}{2}$
  3. $\dfrac{1}{4}$
  4. $\dfrac{1}{6}$
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