What is the vulnerability ? ```c int main (int argc, char...

Multiple choice technology security

What is the vulnerability ?

int main (int argc, char *argv[]) { 
     char k[3]; 
     int i=0,j=1; 
     char buffer[50]; 
     strncpy(buffer, argv[1], sizeof(buffer) - 1); 
     buffer[49]='/0'; 
     unsigned char ch='a'; 
     k[0]=1; 
     do{   
        i++;   
        k[i]=ch+i; 
    } while(i&lt;3); 

    return 0; 
}

Heap overflow
Integer overflow
Off by one error
None of the above

Reveal answer Fill a bubble to check yourself

What is the vulnerability ? int main (int argc, char *argv[]) { char k[3]; int i=0,j=1; char buffer[50]; strncpy(buffer, argv[1], sizeof(buffer) - 1); buffer[49]='/0'; unsigned char ch='a'; k[0]=1; do{ i++; k[i]=ch+i; } while(i&lt;3); return 0; }

Keep practicing — related questions

What is the vulnerability ?

`int main (int argc, char *argv[]) { char k[3]; int i=0,j=1; char buffer[50]; strncpy(buffer, argv[1], sizeof(buffer) - 1); buffer[49]='/0'; unsigned char ch='a'; k[0]=1; do{ i++; k[i]=ch+i; } while(i<3); return 0; }`