Multiple choice technology security

unsigned char j,k; j=getchar(); k=getchar(); unsigned char result = j + k; What vulnerability is present in this code:

  1. Heap Overflow

  2. Integer overflow

  3. Buffer overflow

  4. No Vulnerability
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The variables j and k are declared as unsigned char. Adding two unsigned char values together can yield a sum greater than 255. In C, this arithmetic wraps around due to modulo 256 behavior, resulting in an integer overflow vulnerability.

AI explanation

To answer this question, we need to understand the code and the potential vulnerabilities associated with it.

In the given code snippet:

unsigned char j,k;
j = getchar();
k = getchar();
unsigned char result = j + k;

The vulnerability present in this code is an integer overflow.

Explanation:

  1. The getchar() function reads a character from the standard input and returns its ASCII value as an int.
  2. The ASCII values of characters can range from 0 to 255, which can be represented by an unsigned char in C.
  3. The unsigned char type has a range of 0 to 255.
  4. When adding j and k, the result will be stored in the result variable.
  5. If the sum of j and k exceeds 255, an integer overflow occurs.
  6. An integer overflow happens when the result of an arithmetic operation exceeds the maximum value that can be represented by the data type.
  7. In this case, if the sum of j and k is greater than 255, the result will wrap around and be stored as the remainder of the value modulo 256.
  8. This can lead to unexpected behavior and potential security vulnerabilities if the overflow is not handled properly.

Therefore, the correct answer is B) Integer overflow.

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