Multiple choice technology programming languages

What is the output??(Easy One)

String s1="Java";
String s2="Java";
String s3=new String("Java");
String s4=new String("Java");
if(s1==s2)  System.out.print("true");
else  System.out.println("false");
if(s3==s4)  System.out.print("true");
else  System.out.println("false");
if(s1==s3)  System.out.print("true");
else  System.out.println("false");
if(s2==s3.intern())  System.out.print("true");
else  System.out.println("false");
if(s3.intern()==s2.intern())  System.out.print("true");
else  System.out.println("false");

Just try and get the Ouput---(Ignore any errors)

  1. true false true false true

  2. true false false true true

  3. true false false false true

  4. true false true false false
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

String literals (s1, s2) reference the same string pool object. new String() creates distinct heap objects (s3, s4). The == operator compares references, not content. intern() returns the string pool reference, so comparisons involving intern() yield true when the content is in the pool.

AI explanation

To determine the output of the given code, let's go through each line step by step:

String s1 = "Java";
String s2 = "Java";
String s3 = new String("Java");
String s4 = new String("Java");

In the above code, s1 and s2 are string literals, while s3 and s4 are objects created using the new keyword. 

if(s1 == s2)
    System.out.print("true");
else
    System.out.println("false");

Here, s1 and s2 are both string literals, and they refer to the same object in the string pool. So, the condition s1 == s2 is true, and "true" is printed.

if(s3 == s4)
    System.out.print("true");
else
    System.out.println("false");

In this case, s3 and s4 are two different objects created using the new keyword, so the condition s3 == s4 is false, and "false" is printed.

if(s1 == s3)
    System.out.print("true");
else
    System.out.println("false");

Here, s1 is a string literal and s3 is an object created using the new keyword. They are not the same object, so the condition s1 == s3 is false, and "false" is printed.

if(s2 == s3.intern())
    System.out.print("true");
else
    System.out.println("false");

The intern() method returns the canonical representation of a string object from the string pool. In this case, s3 is interned and refers to the same object as s2. So, the condition s2 == s3.intern() is true, and "true" is printed.

if(s3.intern() == s2.intern())
    System.out.print("true");
else
    System.out.println("false");

Since both s3 and s2 are interned and refer to the same object in the string pool, the condition s3.intern() == s2.intern() is true, and "true" is printed.

Therefore, the output of the given code is:

B. true false false true true

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