To determine the output of the given code, let's go through each line step by step:

String s1 = "Java";
String s2 = "Java";
String s3 = new String("Java");
String s4 = new String("Java");

In the above code, s1 and s2 are string literals, while s3 and s4 are objects created using the new keyword.

if(s1 == s2)
    System.out.print("true");
else
    System.out.println("false");

Here, s1 and s2 are both string literals, and they refer to the same object in the string pool. So, the condition s1 == s2 is true, and "true" is printed.

if(s3 == s4)
    System.out.print("true");
else
    System.out.println("false");

In this case, s3 and s4 are two different objects created using the new keyword, so the condition s3 == s4 is false, and "false" is printed.

if(s1 == s3)
    System.out.print("true");
else
    System.out.println("false");

Here, s1 is a string literal and s3 is an object created using the new keyword. They are not the same object, so the condition s1 == s3 is false, and "false" is printed.

if(s2 == s3.intern())
    System.out.print("true");
else
    System.out.println("false");

The intern() method returns the canonical representation of a string object from the string pool. In this case, s3 is interned and refers to the same object as s2. So, the condition s2 == s3.intern() is true, and "true" is printed.

if(s3.intern() == s2.intern())
    System.out.print("true");
else
    System.out.println("false");

Since both s3 and s2 are interned and refer to the same object in the string pool, the condition s3.intern() == s2.intern() is true, and "true" is printed.

Therefore, the output of the given code is:

B. true false false true true

• Thanks
• Wrong explanation

To answer this question, let's go through each option to understand why it is correct or incorrect:

Option A) 1 and 4 - This option is correct because both -5+5 and "0.00" + 0 can be evaluated to produce a valid result. -5+5 equals 0, and "0.00" + 0 equals "0.00" (a string concatenation).

Option B) 2 and 4 - This option is incorrect because the expression " " is an empty string and cannot be evaluated to produce a valid result. Therefore, option 2 is incorrect.

Option C) 3 and 1 - This option is incorrect because the expression 0X0 is not a valid mathematical expression. It appears to be a typo or incorrect format for multiplication. Therefore, option 3 is incorrect.

Option D) 2 and 3 - This option is incorrect because, as explained earlier, the expression " " is an empty string and cannot be evaluated to produce a valid result. Therefore, option 2 is incorrect.

The correct answer is option A. This option is correct because both -5+5 and "0.00" + 0 can be evaluated to produce valid results.

• Thanks
• Wrong explanation