Multiple choice

Find the surface area of a frustum of cone, whose larger and smaller radius is 25 cm and 12 cm. The slant height of the cone is 30 cm. (Use $\pi$ = 3.14)

  1. 5,600.96 cm$^2$
  2. 5,700.96 cm$^2$
  3. 5,800.96 cm$^2$
  4. 5,900.96 cm$^2$
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D Correct answer
Explanation

The total surface area of a frustum of a cone is given by the formula pi * (R + r) * l + pi * R^2 + pi * r^2. Substituting R = 25, r = 12, and l = 30, we get pi * (37 * 30 + 625 + 144) = 1879 * pi. Using pi = 3.14, this evaluates to approximately 5900.96 square centimeters.

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