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  • Read this piece of code carefully if("String".toString() ...
Multiple choice technology programming languages

Read this piece of code carefully if("String".toString() == "String") System.out.println("Equal"); else System.out.println("Not Equal");Answers

    1. the code will compile an print “Equal”.
    1. the code will compile an print “Not Equal”.
    1. the code will cause a compiler error.
  1. None of Above

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D Correct answer

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