20 Read this piece of code carefully if(" String ".trim() == "String") System.out.println("Equal"); else System.out.println("Not Equal");
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a. the code will compile an print "Equal".
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b. the code will compile an print "Not Equal".
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c. the code will cause a compiler error
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d.
The trim() method creates a new String object in memory even if the resulting trimmed content is identical to an existing literal. Using the == operator compares object references rather than content, so comparing a newly allocated trimmed string to a literal string pool reference evaluates to false.
To answer this question, let's go through each option and analyze the code snippet provided:
Option A) The code will compile and print "Equal".
In the given code snippet, the trim() method is used to remove leading and trailing whitespace from the string " String ". The trim() method returns a new string with the whitespace removed.
However, when comparing strings, the == operator checks for reference equality, not value equality. In Java, the == operator compares the memory addresses of the objects being compared.
In this case, the string " String " is not the same object as the string "String", even though they have the same value after trimming. Therefore, the == comparison will evaluate to false.
So, the code will not print "Equal".
Option B) The code will compile and print "Not Equal".
As explained in Option A, the == comparison will evaluate to false because the strings being compared are different objects. Therefore, the code will print "Not Equal".
Option C) The code will cause a compiler error. There is no compilation error in the given code. The code is syntactically correct, and there are no issues that would cause a compiler error.
Option D) (No option provided) This is not a valid option.
The correct answer is A) The code will compile and print "Equal".