Multiple choice technology

If you compile and execute an application with the following code in its main() method: String s = new String( "Computer" ); if( s == "Computer" ) System.out.println( "Equal A" ); if( s.equals( "Computer" ) ) System.out.println( "Equal B" );

  1. It will not compile because the

  2. "Equal A" is the only thing that is printed

  3. "Equal B" is the only thing that is printed

  4. Both "Equal A" and
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C Correct answer
Explanation

The == operator compares object references, not content. Since new String("Computer") creates a distinct String object in memory, s == "Computer" is false (they point to different objects). The equals() method compares actual string values, so s.equals("Computer") is true, printing "Equal B".

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