Multiple choice technology

void main() { int a=10,b=20; char x=1,y=0; if(a,b,x,y) { printf("EXAM"); } }

  1. XAM is printed

  2. exam is printed

  3. Compiler Error

  4. Nothing is printed
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The comma operator evaluates all operands and returns the value of the last one. The expression (a,b,x,y) evaluates to y=0, which is false. Therefore, the if condition is false and nothing is printed. Note that void main() and missing return are not valid C but are accepted by some compilers as extensions.

AI explanation

To answer this question, let's go through the code snippet step by step:

  1. The main function is defined.
  2. Two integer variables, a and b, are declared and initialized with the values 10 and 20, respectively.
  3. Two character variables, x and y, are declared and initialized with the values 1 and 0, respectively.
  4. An if statement is used with the condition (a, b, x, y).

Now, let's understand the condition (a, b, x, y):

In C++, the comma operator evaluates all its operands (from left to right) and returns the value of the rightmost operand. In this case, the comma operator evaluates a, b, x, and y, but the value of the rightmost operand, y, is discarded.

Since the value of y is 0, which is considered false, the if statement evaluates to false. As a result, the code block within the if statement, which contains the printf statement, is not executed.

Therefore, nothing is printed to the console.

The correct answer is D) Nothing is printed.

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