To determine the values of x
and y
after executing the given code, let's go through each line of the code step by step:
int x=20, y=35;
- This line initializes the variables x
and y
with the values 20 and 35, respectively.
x = y++ + x++;
- This line assigns the value of y++ + x++
to x
.
y++
is a post-increment operation, meaning that the value of y
is used first and then incremented by 1. So, y++
evaluates to 35, and y
becomes 36.
- Similarly,
x++
is a post-increment operation, so x++
evaluates to 20, and x
becomes 21.
- Therefore,
x
is assigned the value 35 + 20 = 55
.
y = ++y + ++x;
- This line assigns the value of ++y + ++x
to y
.
++y
is a pre-increment operation, meaning that the value of y
is incremented by 1 first and then used. So, ++y
evaluates to 37, and y
becomes 37.
- Similarly,
++x
is a pre-increment operation, so ++x
evaluates to 22, and x
becomes 22.
- Therefore,
y
is assigned the value 37 + 22 = 59
.
printf(" %d %d", x, y);
- This line prints the values of x
and y
.
Therefore, the output of the code will be 55 59
.
The correct answer is not listed among the options provided.