To understand the output of this program, let's go through each line of code:
int x=10, y=15;
- This line declares two integer variables x
and y
and initializes them with the values 10 and 15, respectively.
x = x++;
- This line is using the post-increment operator on x
. The post-increment operator increments the value of x
by 1 and returns the original value before the increment. However, since the assignment statement x = x++
is assigning the value of x++
back to x
, the result is undefined behavior. Therefore, it is not recommended to use the post-increment operator in an assignment statement like this. The behavior of this statement is unpredictable.
y = ++y;
- This line is using the pre-increment operator on y
. The pre-increment operator increments the value of y
by 1 and returns the incremented value. So, ++y
will increment the value of y
to 16, and then assign that value back to y
.
printf("%d %dn",x,y);
- This line prints the values of x
and y
.
Given the above code, the output of the program will be "11 16". Therefore, the correct answer is D) 11, 16.