main() { int x=10, y=15; x = x++; y = ++y; printf(“%d %dn”,x,y); }

To understand the output of this program, let's go through each line of code:

1. int x=10, y=15; - This line declares two integer variables x and y and initializes them with the values 10 and 15, respectively.

2. x = x++; - This line is using the post-increment operator on x. The post-increment operator increments the value of x by 1 and returns the original value before the increment. However, since the assignment statement x = x++ is assigning the value of x++ back to x, the result is undefined behavior. Therefore, it is not recommended to use the post-increment operator in an assignment statement like this. The behavior of this statement is unpredictable.

3. y = ++y; - This line is using the pre-increment operator on y. The pre-increment operator increments the value of y by 1 and returns the incremented value. So, ++y will increment the value of y to 16, and then assign that value back to y.

4. printf("%d %dn",x,y); - This line prints the values of x and y.

Given the above code, the output of the program will be "11 16". Therefore, the correct answer is D) 11, 16.

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